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Lilit [14]
3 years ago
10

How are you supposed solve x

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
7 0
Because the lines are parallel, 75 is equal to 11x-2
75=11x-2
77=11x
x=7
marin [14]3 years ago
7 0
75 would be congruent to 11x - 2 so you set them equal to each other.

75 = 11x - 2
77 = 11x
x = 7
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Are 8x+ 16 and 4(2x+4) equivalent
8090 [49]
Yes they are equivalent
8 0
3 years ago
If 120% is £360 what is 100%
AleksAgata [21]
In this question a vital information has been provided. This information can be used for determining the answer to the question that is asked. It is given that 120% of a certain number is 360 pound. The 100% value of the number needs to be determined.
Let us assume the number to be = x
Then
120x/100 = 360
12x/10 = 360
12x = 360 * 10
12x = 3600
x = 3600/12
   = 300
 Now we can say that the 100% of the number or the actual number is 300 pounds. I hope the problem is clear to you and you can understand the trick involved in the question.
6 0
3 years ago
Find the angle between the vectors u=i-9j and v=8i+5j
Katyanochek1 [597]

Answer: \cos^{-1} \left(\frac{-37}{\sqrt{7298}} \right) \approx 115.665^{\circ}

Step-by-step explanation:

u \cdot v=(1)(8)+(-9)(5)=-37\\\\|u|=\sqrt{1^{2}+(-9)^{2}}=\sqrt{82}\\\\|v|=\sqrt{8^{2}+5^{2}}=\sqrt{89}\\\\\cos \theta=\frac{-37}{\sqrt{82}\sqrt{89}}\\\\\theta=\cos^{-1} \left(\frac{-37}{\sqrt{82}\sqrt{89}} \right)\\\\\theta=\boxed{\cos^{-1} \left(\frac{-37}{\sqrt{7298}} \right) \approx 115.665^{\circ}}

7 0
2 years ago
Please help :D <3. Do not understand this one.
Shtirlitz [24]
Sorry for my messy handwriting but this is the answer

8 0
3 years ago
A positive real number is 6 less than another. If the sum of the square of the two numbers is 38, then finds the numbers.
Serggg [28]

Answer:

There seems to be a typo error but still this has solution.

Let the number be = x

A positive real number is 6 less than another. Means the second will be (x+6)

The sum of the square of the two numbers is 38.

x^{2} +(x+6)^{2} =38  

=> x^{2} +36+12x+x^{2} =38

=> 2x^{2}+12x+36 =38

=> 2x^{2}+12x=2

=> 2x^{2}+12x-2=0

Taking out 2 common;

=> x^{2}+6x-1=0

Solving this quadratic equation, we get;

x=-3+\sqrt{10} and x=-3-\sqrt{10}

As positive number is needed, we have -3+\sqrt{10}

or x = \sqrt{10}-3

x = 0.162277

And other number is 6.162277.

6 0
3 years ago
Read 2 more answers
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