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Lilit [14]
3 years ago
10

How are you supposed solve x

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
7 0
Because the lines are parallel, 75 is equal to 11x-2
75=11x-2
77=11x
x=7
marin [14]3 years ago
7 0
75 would be congruent to 11x - 2 so you set them equal to each other.

75 = 11x - 2
77 = 11x
x = 7
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GIVING 100 POINTS!!!!
IrinaK [193]

Answer:

As per dot plots we see the distribution of prices is close but majority of prices are concentrated in different zones. So MAD would be more similar by the look.

<u>Let's verify</u>

<h3>Neighborhood 1</h3>

<u>Data</u>

  • 55, 55, 60, 60, 70, 80, 80, 80, 90, 120

<u>Mean</u>

  • (55*2+ 60*2+ 70+ 80*3 + 90+ 120)/10 = 75

<u>MAD</u>

  • (20*2+15*2+5+5*3+15+45)/10 = 15
<h3>Neighborhood 2</h3>

<u>Data</u>

  • 100, 110, 110, 110, 120, 120, 120, 140, 150, 160

<u>Mean</u>

  • (100 + 110*3+ 120*3+ 140 + 150+ 160)/10 = 124

<u>MAD</u>

  • (24+14*3+4*3+16*3+16+26+36)/10 = 20.4

As we see the means are too different (75 vs 124) than MADs (15 vs 20.4).

7 0
3 years ago
Read 2 more answers
Here’s another one free 50 points and brainiest, first come first serve!<br> 4x+5-10+3x=57
GarryVolchara [31]
So we have to simplify this equation:
4x+5-10+3x=57
Add like terms:
7x-5=57
Then add 5 to both sides:
7x=62
x=62/7
3 0
3 years ago
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How would I put this into a solvable equation, m= ak/n?
12345 [234]

The given equation is

m = ak/n

We want to solve for k

The first step is to multiply both sides of the equation by n. We have

m * n = ak/n * n

mn = ak

The next step is to divide both sides of the equation by a. We have

mn/a = ak/a

mn/a = k

k = mn/a

The correct option is the second one

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1 year ago
How do I solve this system of equations by adding, subtracting, or multiplying? <br> x-y=8;x+y=12
Natasha2012 [34]
By substitution.
Get y or x alone then insert it into the other equation solving for one of the two variables. After that substitute ur answer into one of the equations then solve.
7 0
3 years ago
Using t=tanx/2, write an expression for sinx and cosx in terms of t.
Dafna11 [192]

Assume 0 < <em>x</em>/2 < <em>π</em>/2. Then

tan²(<em>x</em>/2) + 1 = sec²(<em>x</em>/2)   ===>   sec(<em>x</em>/2) = √(1 - tan²(<em>x</em>/2))

===>   cos(<em>x</em>/2) = 1/√(1 - tan²(<em>x</em>/2))

===>   cos(<em>x</em>/2) = 1/√(1 - <em>t</em> ²)

We also know that

sin²(<em>x</em>/2) + cos²(<em>x</em>/2) = 1   ===>   sin(<em>x</em>/2) = √(1 - cos²(<em>x</em>/2))

Recall the double angle identities:

cos(<em>x</em>) = 2 cos²(<em>x</em>/2) - 1

sin(<em>x</em>) = 2 sin(<em>x</em>/2) cos(<em>x</em>/2)

Then

cos(<em>x</em>) = 2/(1 - <em>t</em> ²) - 1 = (1 + <em>t</em> ²)/(1 - <em>t</em> ²)

sin(<em>x</em>) = 2 √(1 - 1/(1 - <em>t</em> ²)) / √(1 - <em>t</em> ²) = 2<em>t</em>/(1 - <em>t</em> ²)

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2 years ago
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