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zavuch27 [327]
2 years ago
7

How do you even do this???

Mathematics
1 answer:
kolbaska11 [484]2 years ago
6 0
Tell whether the product of Prxs and Q5x3 is defined. If so, give the dimensions of PQ.

undefined
defined; 7 x3
defined; 3 x 7
defined; 5 x 5
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4x - 7 (2 - x) = 3x + 2
juin [17]

Answer:

x=2

Step-by-step explanation:

4x−7(2−x)=3x+2

4x+(−7)(2)+(−7)(−x)=3x+2(Distribute)

4x+−14+7x=3x+2

(4x+7x)+(−14)=3x+2(Combine Like Terms)

11x+−14=3x+2

11x−14=3x+2

Step 2: Subtract 3x from both sides.

11x−14−3x=3x+2−3x

8x−14=2

Step 3: Add 14 to both sides.

8x−14+14=2+14

8x=16

Step 4: Divide both sides by 8.

x=2

3 0
3 years ago
Which of the following is an X-intercept of the function f(X)=X^3-5X^2-8X+48
Anton [14]
You have to searh the x values that make f(x) = 0

Factoring this equation is very difficult.

You can divide by x+3 and you will find that the equation can be factored as

(x+3)(x-4)^2

That means that x = -3 and x = 4 make f(x) = 0

Then the points are (-3,0) and (4,0).
6 0
3 years ago
Estimate √38.7 to the nearest integer
Murljashka [212]
Well 6^2 is 36 so my best estimate is 6
7 0
3 years ago
Read 2 more answers
Division of whole numbers is associative, true or false? If false then what is correct? Plz and Thank you for the help!!
Sav [38]

Answer:

Division is not associative.

The associative property applies only to addition and multiplication, not subtraction or division.

4 0
3 years ago
Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data
tresset_1 [31]

Based on the information represented by the boxplot ;

  • Latasha's lowest sale amount = 50

  • Kayla's median is between 200 and 300

  • Latasha has a greater spread due to higher IQR value

1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>

  • The minimum value is denoted by the starting position of the lower whisker on a boxplot.

  • Lowest amount of sale made by Latasha = 50

2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>

  • 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

  • 50% of sales made by Kayla is between 200 and 300

  • With median sale value being 250

3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>

  • The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

  • IQR = Upper Quartile (Q3) - Lower quartile(Q1)

<u>For Latasha</u> :

  • Q3 = 450 (Endpoint of the box)
  • Q1 = 150 (starting point of the box)

  • IQR = 450 - 150 = 300

<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>

  • Q3 = 375 (Endpoint of the box)
  • Q1 = 100 (starting point of the box)
  • IQR = 375 - 100 = 275

  • Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

4 0
2 years ago
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