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3 years ago

12

Can someone help me define these triangles.

1 answer:

lana66690 [7]3 years ago

4 0

Answer:

Scalene: F, B

Equilateral: H, D, C

Isosceles: G, E, A,

Hope this helped!

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cluponka [151]

Answer:

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Step-by-step explanation:

...look at those numbers dude

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3 years ago

Show all work and find the derivativve of the function

shepuryov [24]

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3 years ago

Determine whether each expression can be used to find the length of side AB. Match Yes or No for each

tankabanditka [31]

Answer:

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

Step-by-step explanation:

Given

$BC =24$

$AC = 7$

Required

Select Yes or No for the given options

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

Considering the sine of angle B, we have:

$\sin(B) = \frac{Opposite}{Hypotenuse}$

$\sin(B) = \frac{7}{AB}$

Make AB, the subject

$AB = \frac{7}{\sin(B)}$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

Considering the cosine of angle B, we have:

$\cos(B) = \frac{Adjacent}{Hypotenuse}$

$\cos(B) = \frac{24}{AB}$

Make AB the subject

$AB = \frac{24}{\cos(B)}$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

Considering the cosine of angle B, we have:

$\cos(A) = \frac{Adjacent}{Hypotenuse}$

$\cos(A) = \frac{7}{AB}$

Make AB the subject

$AB = \frac{7}{\cos(A)}$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

<em>This has been shown in (c) above</em>

3 0

3 years ago

Answer fast!! With explanation pls

Zepler [3.9K]

D is equivalent because brackets don’t change anything here

4 0

2 years ago

Read 2 more answers

A circular light fixture has a radius of 20 centimeters. what is the circumference of the light fixture? use 22/7 for pi

kirza4 [7]

So you do 22/7 × 40 = 125.71428571

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3 years ago