What is the slope of the line y=x+15
1 answer:
You might be interested in
Answer:
The attendance was 198 children, 90 students and 99 adults.
Step-by-step explanation:
We define:
c: children attendance
s: students attendance
a: adult attendance
The equation that describes the total ticket sales is:
We also know that the children attendance doubles the adult attendance:
The third equation is the seating capacity, which we assume is full:
We start by replacing variables in two of the equations:
Then, we solve the remaining equation for a:
Then, we solve for the other two equations:
The attendance was 198 children, 90 students and 99 adults.
Answer:
1,805 kg.
Step-by-step explanation:
We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.
First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.
Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.
Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.