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oee [108]
3 years ago
12

What do i point on the graph ?

Mathematics
1 answer:
ehidna [41]3 years ago
8 0

Answer:

so there is a y and a x axis the x axis is on the bottem and the y axis is on the left

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Use prime factors to find hcf of 18 12 56​
givi [52]

Answer:

it is 2 bcz if we see that in the 12 , 18 and 56 the two is the highest common factor

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3 years ago
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A catcher's and a pitcher's uniform numbers are consecutive integers whose product is 132. If the catcher's was the smaller numb
Masja [62]

Answer:

  • catcher: 11
  • pitcher: 12

Step-by-step explanation:

Since the numbers are consecutive, the square root of the product will be a value between them.

  √132 ≈ 11.49

so, the consecutive numbers are 11 and 12. (11×12 = 132)

The catcher's number is smaller, so is 11; the pitcher's number is 12.

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4 years ago
Help me with this one
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672 hope that help we learned that this year
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What value of x is in the solution set of 3(x-4) ≥ 5x+2
Sunny_sXe [5.5K]

Answer:

x<u><</u> -7

Step-by-step explanation:

3 0
3 years ago
A company establishes a fund of 120 from which it wants to pay an amount,C, to any of its 20 employees who achieve a high-perfor
Leno4ka [110]

Answer:

C=120/2=60

Step by step Explanation'

To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.

For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.

Determine the maximum value of C, then the maximum value that C can have is 120/n

Let us represent X as the number of employees with high performance with a binomial distribution of

P =0.02( since the percentage of chance of achieving a high performance level is 2%)

n = 20 ( number of employees who achieve a high performance level)

The probability of X= 0 can be calculated

P( X= 0) = 0.98^n

P(X=0)=0.98^20

P(X=0)=0.668

P(X=1)=0.02*20*0.98^19

P(X=1)=0.272

P(X=2)=0.02^2*20*0.98^18

P(X=2)=0.053

Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)

BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,

Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2

then the maximum value that C can have is 120/n

C=120/2=60

7 0
4 years ago
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