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zysi [14]
3 years ago
13

Last year at a certain high school, there were 100 boys on the honor roll and 84 girls on the honor roll. This year, the number

of boys on the honor roll increased by 17% and the number of girls on the honor roll increased by 25%. By what percentage did the total number of students on the honor roll increase? Round your answer to the nearest tenth (if necessary).
Mathematics
1 answer:
-BARSIC- [3]3 years ago
6 0

Answer:

I Think the honor of total students is 50%

Step-by-step explanation:

25 +17=45

Round 45 to the nearest tenth and you get 50

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Answer:

  x = 64 m

Step-by-step explanation:

The scale is proportional to the actual:

  (6 m)/(3/4 cm) = x/(8 cm)

Multiplying by 8 cm, we get ...

  x = (8 cm)·(6 m)/(3/4 cm)

  x = 64 m . . . . the width of the actual wall

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Step-by-step explanation:

If you look at the points, they are traveling up and to the right. So is the line in the graph. Also, the line in the graph is closer to more dots than the others.

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What unit of measurement would you use to weigh an adult?
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Step-by-step explanation:

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Wendy needs to purchase 25 vases, which cost $3 each, and flowers for the vases, which cost $2 each. She has $275 to spend on he
Levart [38]
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5 0
3 years ago
A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
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