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2 years ago

2|4x-5|-2=-4 how do I solve this?

Mathematics

1 answer:

EastWind [94]2 years ago

7 0

Step-by-step explanation:

in my opinion

2(4x-5)-2=-4

=2×4x-2×5-2=-4

8x-10-2=-4

8x=-4+10+2

8x=-4+12

8x=-16(divide both sides by 8)

×=2

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Suppose you could choose 2 boxes of markers. Find all the possible pairs. 15 markers 24 markers 36 markers 48 markers. Find all

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3 years ago

Read 2 more answers

If G is the circumcenter of triangle ABC, AG = 6x + 1, GC = 9x – 11, and BC = 38, find GF.

maks197457 [2]

Answer:

GF = 16.25

Step-by-step explanation:

If G is the circumcenter of triangle ABC, AG = 6x + 1, GC = 9x – 11, and BC = 38, find GF.

Step 1

We find x

AG = GC

6x + 1 =9x - 11

Collect like terms

1 + 11 = 9x - 6x

12 = 3x

x = 12/3

x = 4

Step 2

We solve for AG

GC = 9x + 11

GC = 9(4) + 11

GC = 36 + 11

GC = 25

Step 3

Solving for GF, using Pythagoras Theorem

GF² + BG² = GC²

GF² = GC² - BG²

GF = √GC² - BG²

GF = √25² - 19²

GF = √264

GF = 16.248076809

GF = 16.25

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2 years ago

Look at the formula for the area of a triangle. a = 1 2 bh which is a solution for h?

andrey2020 [161]

Answer: h = 2a/b

Explanation:

$a = \cfrac{1}{2} bh$

$2a = bh$

$bh = 2a$

$h = \cfrac{2a}{b}$

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3 years ago

(a) An angle measures 140 . What is the measure of its supplement? (b) An angle measures 36 . What is the measure of its complem

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3 years ago

There were 324 adults surveyed. Among the participants, the mean number of hours of sleep each night was 7. 5 and the standard d

NeTakaya

The margin of error for 324 adults surveyed with 1.6 standard deviations is 0.1742.

<h3>What is the margin of error?</h3>

The margin of error can be defined as the amount of random sampling error in the results of a survey. It is given by the formula,

$\text{MOE}_{\gamma}=z_{\gamma} \times \sqrt{\frac{\sigma^{2}}{n}}$

$\text{MOE}$ = margin of error

$\gamma$ = confidence level

$z_{\gamma}$ = quantile

σ = standard deviation

n = sample size

As it is given that the sample size of the survey is 324, while the standard deviation of the survey is 1.6.

We know that the value of the z for 95% confidence interval is 1.96. Therefore, using the formula of the standard of error we can write it as,

$\text{MOE}_{\gamma}=z_{\gamma} \times \sqrt{\dfrac{\sigma^{2}}{n}}\\\\\text{MOE}_{\gamma}=1.96 \times \sqrt{\dfrac{1.6^{2}}{324}}\\\\\text{MOE}_{\gamma}=0.1742$

Hence, the margin of error for 324 adults surveyed with 1.6 standard deviations is 0.1742.

Learn more about Margin of Error:

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2 years ago

2|4x-5|-2=-4 how do I solve this?​

2|4x-5|-2=-4 how do I solve this?