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3 years ago

11

The length of a garden can be expressed as 2X +6 feet and the width is X +7 feet what is the perimeter of the garden what is the

area

1 answer:

Virty [35]3 years ago

6 0

Answer:

6x + 26 feet

Step-by-step explanation:

Assuming the garden is a rectangular shape, we have four sides, where two sides are 2x + 6 feet and two sides are x + 7 feet. To find the perimeter, we add up the lengths of all four sides.

2x + 6 + 2x + 6 + x + 7 + x + 7

or

2(2x + 6) + 2(x + 7)

6x + 26

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Help I need it now!!<br> T14= 46, and t20= 100, find t3, t7, and tn

Vinil7 [7]

Answer:

$t_3 = -53\\\\\\t_7 = -17\\t_n= -80 +9n$

Step-by-step explanation:

Arithmetic sequence:

$\sf \boxed{t_n=a+(n-1)d}$

Here a is the first term and d is the common difference.

$t_{14}= 6$ ⇒ $\sf a + 13 d = 46$ ------------(I)

$\sf t_{20} = 100$ ⇒ a + 19d = 100 ---------(II)

Subtract equation (I) from (II)

(I1) a + 19d = 100

(II) a + 13d = 46

<u>- - -</u>

6d = 54

d = 54 ÷ 6

$\sf \boxed{d = 9}$

Substitute d = 9 in equation(I) and find 'a',

a + 13*9= 46

a + 117 = 46

a = 46 - 117

a = -71

$\sf t_3 = -71 + 2*9$

= -71 + 18

= -53

$\sf t_7 = -71 + 6*9$

= -71 + 54

= -17

$\sf t_n= -71 + (n-1)*9$

= -71 + 9*n - 1 *9

= -71 + 9n - 9

= -71 - 9 + 9n

= - 80 + 9n

5 0

1 year ago

(a^3+a^2b/5a)(25/3b+3a)

zheka24 [161]

Answer:

$\frac{5a}{3}$

Step-by-step explanation:

The given expression is;

$(\frac{a^3+a^2b}{5a})(\frac{25}{3b+3a} )$

Factorize;

$(\frac{a^2(a+b)}{5a})(\frac{25}{3(b+a)} )$

Cancel out the common factors;

$(\frac{a(1)}{1})(\frac{5}{3(1)} )$

Simplify;

$\frac{5a}{3}$

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3 years ago

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X^2-18x-6. complete the square

vlabodo [156]

Answer:

$(x-9)^2-87$

Step-by-step explanation:

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Which is an appropriate estimate

saveliy_v [14]

Answer:

40

Step-by-step explanation:

This answer is the closest when it comes to 3,844 divided by 75.

6 0

3 years ago

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Consider rolling two fair dice and observing the number of spots on the resulting upward face of each one. Letting A be the even

Allushta [10]

Answer:

$P(E|A)= \frac{10}{11}$

Step-by-step explanation:

Given

Two rolls of die

$E \to$ one of the outcomes is 6

$A \to$ atleast one is 6

Required

P(E|A)

First, list out the outcome of each

$E = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}$

$A = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}$

So:

$P(E|A)= \frac{n(E\ n\ A)}{n(A)}$

Where:

$E\ n\ A = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}$

$n(E\ n\ A) = 10$

$n(A) = 11$

So:

$P(E|A)= \frac{10}{11}$

7 0

3 years ago