This isn't really a geometry problem. It's just an addition of fractions.
You know that 'perimeter' means 'the distance all the way around'.
And you know the length of all the sides of the parallelogram.
All you need to do is add them up !
(13/12) + (3/13) + (13/12) + (3/13) = the perimeter
Notice that two of the sides are equal, and the other two sides are also equal.
So you can make the job a little easier if you add up the twelfths first
(13/12) + (13/12) = 26/12
and then add up the thirteenths ...
(3/13) + (3/13) = 6/13 .
Now, the perimeter looks a little bit less complicated.
It's just
(26/12) + (6/13) = the perimeter.
This is the tough part. Before you can add fractions, they need to have
a common denominator.
The smallest common denominator for 12ths and 13ths is <em>156 </em>!
Change each fraction to (<em>something over 156</em>), and add um up.
I'll leave that part to you.
Answer:
A
Step-by-step explanation:
Answer:
HI = 8
TU = 45
Step-by-step explanation:
→ Find the scale factor enlargement
45 ÷ 10 = 4.5
→ Multiply JI by the scale factor to find it
10 × 4.5 = 45
→ Divide UV by the scale factor to find it
36 ÷ 4.5 = 8
Answer:
the correct one is c, which is the second option
Step-by-step explanation:
The exterior angle of a polygon is 360.
And for a rectangle, they have equal exterior angles.
So a rectangle has 4 sides
So each exterior angle=360/4
Then each is 90°
Then the correct c which has 90°
Given
Height (length) of the anchor dropped from the boat = 75 feet
Distance of the treasure from the anchor = 40 feet
Solution
The dropped at the bottom makes an angle of 90 degree . Therefore making an right triangle with the chest and boat
By Pythagoras theorem
AC^2 = AB^2 + BC^2
(AC = distance of the treasure from the boat
AB = height of the anchor dropped from the boat
BC = the distance of treasure from the anchor)
AC^2 = 75^2 + 40^2
AC^2 = 5325 +1600
AC^2 = 6925
AC = 25 * (under root 11)
Therefore they have cover a distance of 25 * (under root 11)
