Question

What is the rate constant of a reaction if rate = 1 x 10^-2 (mol/L)/s, [A] is 2 M,

Answer 1

Answer:

D. 8.3 x 10-4

Explanation:

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In this case, since the rate law is written solving for the rate constant as:

$k=\frac{r}{[A]^2[B]}$

Thus, we plug the rate and concentrations to obtain:

$k=\frac{0.01M/s}{(2M)^2(3M)}\\\\k=8.3x10^{-4}M^{-2}s^{-1}$

Therefore, the answer would be D. 8.3 x 10-4

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