Answer: 60.7 g of 
will be formed.
Explanation:
To calculate the moles :
The balanced chemical reaction is
is the limiting reagent as it limits the formation of product and 
is the excess reagent.
According to stoichiometry :
6 moles of produce = 4 moles of
Thus 2.68 moles of will produce=
of
Mass of 
Thus 60.7 g of will be formed by reactiong 60 L of hydrogen gas with an excess of
Answer:
because not enough of the parent isotope remains to measure accurately. because not enough of the daughter product has formed to be detectable.
Explanation:
Hope it helps
Answer:
Overall reaction equation;
2NO(g) +Cl2(g) -----> 2NOCl (g)
Explanation:
Given
1) NO(g) + Cl2(g) → NOCl2(g)
2) NOCl2(g) + NO(g) → 2NOCl(g)
Overall reaction equation;
2NO(g) +Cl2(g) -----> 2NOCl (g)
k1= [NOCl2]
k-1= [NO] [Cl2]
k2 = [NOCl2] [NO]
Equilibrium for the first equation (reaction 1)
K= k1/k-1 = [NOCl2]/[NO] [Cl2]
Therefore
[NOCl2] = k1/k-1 [NO] [Cl2]
Rate= k2× k1/k-1 [NO]^2 [Cl2]
Rate = Koverall [NO]^2 [Cl2]
Where Koverall= k1k2/k-1
the reagents necessary to convert alcohol to ketone
which involves oxidation of alcohols.
<h3>
What is oxidation of alcohols?</h3>
- Alcohol oxidation is a significant organic chemistry process. Secondary alcohols can be oxidized to produce ketones, while primary alcohols can be oxidized to produce aldehydes and carboxylic acids.
- In contrast, tertiary alcohols cannot be oxidized without the C-C bonds in the molecule being broken.
- In order to cause primary alcohols to oxidize into aldehydes
(dichromate)
/pyridine (Collins reagent)- Chromium pyridinium compound (PCC)
- Dichromate of pyridinium (PDC, Cornforth reagent)
- Periodinane by Dess-Martin
- Oxalyl chloride with dimethylsulfoxide (DMSO) for Swern
- oxidation of secondary alcohols to ketones
- (dichromate)
- /pyridine (Collins reagent)
- Chromium pyridinium compound (PCC)
- Dichromate of pyridinium (PDC, Cornforth reagent)
- Periodinane by Dess-Martin
- Oxalyl chloride and dimethyl sulfoxide (DMSO) (Swern oxidation)
/acetone (Jones oxidation)- Acetone with aluminum isopropoxide (Oppenauer oxidation)
To learn more about oxidation of alcohols with the given link
brainly.com/question/7207863
#SPJ4
<u>Question:</u>
Identify the reagents necessary to achieve each of the following transformations
Part 1)
when the balanced equation for this reaction is:
and by using ICE table
Mg(OH)2(s) ↔ Mg2+(aq) + 2OH-(aq)
initial 0 0
change +X +2X
Equ X 2X
When KSp expression = [Mg2+][OH-]
when we have KSp = 5.61 x 10^-11
and when we assumed [Mg2+] = X
and [ OH-] = (2X)^2
when we assume X is the value of molar solubility of Mg(OH)2
so, by substitution:
5.61 x 10^-11 = 4X^3
∴ X = 2.4 x 10^-4 M
∴ molar solubility of Mg(OH)2 = X = 2.4 x 10^-4 M
Part 2)
the molar solubility of Mg(OH)2 in 0.16 m NaOH we assumed it = X
by using the ICE table:
Mg(OH)2(s) → Mg2+(aq) + 2OH-
initial 0 0.16m
change +X +2X
equ X (0.16+2x)
when Ksp = [mg2+][OH-]^2
5.61 x 10^-11 = X * (0.16+2X)^2 by solving for X
∴ X = 1.3 x 10^-5 M
∴ the molar solubility = X = 1.3 x 10^-5 M
