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3 years ago

The small structures in the cell that carry out the cell's activities are known as

Chemistry

1 answer:

Colt1911 [192]3 years ago

7 0

The answer is o<span>rganelles.</span>

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3 years ago

An electron that is in the highest energy level of an atom and determines the atom's chemical properties is called a(n)

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The answer is C: Valence electron

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3 years ago

2 A certain gas of 25 g at 25°c and 0.65 atm occupies a volume of 23.52L Determine the molecule mass of the gas.

denpristay [2]

Answer:

${ \bf{PV= \frac{m}{M} RT}} \\ \\ { \tt{(0.65 \times 23.52) = \frac{25}{M} \times 0.081 \times (25 + 273)}} \\ \\ M = 39.5 \: g$

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3 years ago

What happens to the amplitude of waves when two waves overlap and are out of phase with each other?

11Alexandr11 [23.1K]

Answer:

Also called superposition. When overlapping waves produce a wave with an amplitude that is the sum of the individual waves. When overlapping waves produce a wave with an amplitude that is less than the sum of the individual waves.

Explanation:

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3 years ago

At what time will the pressure of SO₂Cl₂ decline to 0.50 its initial value? Express your answer using two significant figures.

QveST [7]

Answer: The time is 0.69/k seconds

Explanation:

The following integrated first order rate law

ln[SO₂Cl₂] - ln[SO₂Cl₂]₀ = - k×t

where

[SO₂Cl₂] concentration at time t,

[SO₂Cl₂]₀ initial concentration,

k rate constant

Therefore, the time elapsed after a certain concentration variation is given by:

$t=\frac{ln[SO_{2}Cl_{2}]_{0} - ln[SO_{2}Cl_{2}]}{k}=\frac{ln\frac{[SO_{2}Cl_{2}]_{0}}{[SO_{2}Cl_{2}]} }{k}$

We could assume that SO₂Cl₂ behaves as a ideal gas mixture so partial pressure is proportional to concentration:

$p_{(SO_{2}Cl_{2})}V = n_{(SO_{2}Cl_{2})}RT$

$[SO_{2}Cl_{2}]= \frac{n_{(SO_{2}Cl_{2})}}{V}}=\frac{p_{(SO_{2}Cl_{2})}}{RT}}$

In conclusion,

t = ln( p(SO₂Cl₂)₀/p(SO₂Cl₂) )/k

$t=\frac{ln\frac{p_{(SO_{2}Cl_{2})}_{0}}{p_{(SO_{2}Cl_{2})}} }{k}$

for

$p_{(SO_{2}Cl_{2})}=0.5p_{(SO_{2}Cl_{2})}_{0}$

$t=\frac{ln\frac{p_{(SO_{2}Cl_{2})}_{0}}{0.5p_{(SO_{2}Cl_{2})_{0}}} }{k}$

$t=\frac{ln\frac{1}{0.5} }{k}$

$t=\frac{ln(2)}{k}$

$t=\frac{0.69}{k}}$

7 0

3 years ago