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Flura [38]
3 years ago
8

Create a system of equations to represent the word problem. Then solve using the linear combination/elimination method. Show all

your work. Adam's Printing Inc. has two types of printing presses: Model A and Model B. Model A can print 80 books per day and Model B can print 55 books per day. Altogether Adam has 9 printing presses. If he can print 670 books in a day, then how many of each press does he have?
Mathematics
2 answers:
Leno4ka [110]3 years ago
8 0

Answer:

Solution given:

model A printers [a] prints=80books per day

model B printers [b] prints=55books per day

total no of printers =9

no of model A printers be x

and

no of model B printers be [9-x]

According to the question;

ax+(9-x)b=670 books

substituting value of a and b; we get

80x+(9-x)55=670

80x-55x+495=670

25x=670-495=175

x=\frac{175}{25}=7

So;

no of model A printers =x=<u>7</u>

no of model B printers =9-x=9-7=<u>2</u>

<u>is</u><u> </u><u>your</u><u> </u><u>answer</u><u>.</u>

zysi [14]3 years ago
4 0

GIVEN:

  • <u>Model A</u>:— 80books/day. (a)
  • <u>Model B</u>:— 55books/day. (b)

ANSWER:

Let number of progression Model A be x then Model B be (9 - x).

According to question,

  • ax + (9 - x)b = 670

Plugging the respective value.

  • 80x + (9 - x)55 = 670
  • 80x - 55x + 495 = 670
  • 25x = 670 - 495
  • 25x = 175
  • x = 7.

Therefore, No. of Model A printers is 7 and No. of Model B printers is 2.

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Answer:

Step-by-step explanation:

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Solve the quadratic equation using factorization method

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x = 3 x = -7

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2. Same solution as number 1

3. Let

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Area of a rectangle = length × width

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2x^2 - 3x - 9 = 0

Solve using quadratic formula

a = 2

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c = -9

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= 3 +or- √ 9 - (-72) / 4

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x = (3 + 9)/4 or (3 - 9) / 4

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So,

Width = x = 3 ft

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= 2(3) - 3

= 6 - 3

= 3ft

2.if the sum of the square of the number and 4 time that number is 21 the what is the number?

3. the length of the rectangle is 3 less than twice the width. if the area is 9 square ft, the length and width of the rectangle.

4.given the figure below. find the area of the shaded part of the rectangle if the area of the big but angle is 6 times the area of the unshaded rectangle ​

Unshaded area

Length = 2x

Width = x

Shaded area

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Area of the shaded area = 6 × the unshaded area

(2x) (x) = 6(2x + 3)(x+3)

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2x^2 = 12x^2 + 36x + 9x + 54

2x^2 = 12x^2 + 45x + 54

12x^2 + 45x + 54 - 2x^2 = 0

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