Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)
we just need the slope
take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1
the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation
solve for where y=x-1 and y=x-x² intersect
set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero
x-1=0
x=1
we got this point already
x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2
it intersects at (-1,-2)
Red Bull and Buffalo Wild Wings
Answer:
x+3y+z=21
Step-by-step explanation:
x+3y+z
4+3(5)+2
4+15+2
21
Answer:
9.2 ft
Step-by-step explanation:
The shape is a triangle, the 11 ft is your hypotenuse
You need to use the Pythagorean Theorem!
a^2 + b^2 = c^2 (solve for a, the missing length that they ask for)
so --->
a^2 + (6^2) = 11^2
a^2 + 36 = 121
~subtract 36 to the right side~
a^2 = 85
now find the square root of 85:
a = 9.21954
round it to the nearest tenth:
a = 9.2
final answer: 9.2 ft
hope this helpsss
