Answer:
m = 0.2508 g
Step-by-step explanation:
We know that for continuous exponential decay, we usually use the format;
N = N_o•e^(kt)
Where N and N_o represent amount after time t and intial amount respectively. And k is decay rate.
But in this case, we are dealing with mass.
Thus, we will use;
m = m_o•e^(-kt)
We are given;
Initial mass; m_o = 0.5 g
Time after decay; t = 60 days
Decay rate; k = 1.15% per day = 0.0115 per day
Thus;
m = 0.5e^(-0.0115 × 60)
m = 0.5 × 0.5016
m = 0.2508 g
Answer:
1) m ∠B = 132°
2) m ∠B = 113°
Step-by-step explanation:
1. In triangle ABC, m ∠A=36, and m ∠C=12. Calculate m ∠B.
We are given measure of 2 angles and we need to find the third angle.
We know that, sum of angles of triangle = 180°
We can write as:
∠A + ∠B + ∠C = 180°
Now put m ∠A=36 and m ∠C=12, to find m ∠B
![\angle A + \angle B + \angle C = 180\\36+ \angle B +12=180\\\angle B+48=180\\\angle B=180-48\\\angle B=132](https://tex.z-dn.net/?f=%5Cangle%20A%20%2B%20%5Cangle%20B%20%2B%20%5Cangle%20C%20%3D%20180%5C%5C36%2B%20%5Cangle%20B%20%2B12%3D180%5C%5C%5Cangle%20B%2B48%3D180%5C%5C%5Cangle%20B%3D180-48%5C%5C%5Cangle%20B%3D132)
So, we get m ∠B = 132°
2. In triangle ABC, m ∠A=40, and m ∠C=27. Calculate m ∠B.
We are given measure of 2 angles and we need to find the third angle.
We know that, sum of angles of triangle = 180°
We can write as:
∠A + ∠B + ∠C = 180°
Now put m ∠A=40 and m ∠C=27, to find m ∠B
![\angle A + \angle B + \angle C = 180\\40+ \angle B +27=180\\\angle B+67=180\\\angle B=180-67\\\angle B=113](https://tex.z-dn.net/?f=%5Cangle%20A%20%2B%20%5Cangle%20B%20%2B%20%5Cangle%20C%20%3D%20180%5C%5C40%2B%20%5Cangle%20B%20%2B27%3D180%5C%5C%5Cangle%20B%2B67%3D180%5C%5C%5Cangle%20B%3D180-67%5C%5C%5Cangle%20B%3D113)
So, we get m ∠B = 113°
Answer:
Step-by-step explanation:
b
Answer:
C
Step-by-step explanation:
3^2 + 5^2 = x^2
9 + 25 = x^2
x^2 = 34
x = sqrt(34)
so the answer is C