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andrew-mc [135]
3 years ago
14

The movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your an

swer.
Match each expression on the left with its equivalent on the right. Some answer choices on the right will not be used.

Mathematics
1 answer:
OLEGan [10]3 years ago
5 0

Answer:

8200 * 100 = 820,00

820,000 ÷ 10 = 82,000

820 * 10 = 8200

82,000 ÷ 1,000 = 82

Step-by-step explanation:

Love your username btw

You might be interested in
Simplify the expression<br><br>cot^2x - cot^2x cos^2x
andrew-mc [135]
Cot^2x - cot^2x cos^2x
= cot^2x - {(cot^2x)(cos^2x)}
= cot^2x { 1 - cos^2x }
= cot^2x { sin^2x }
= (cos^2x/sin^2x) { sin^2x }
= cos^2x
8 0
3 years ago
Would like scatter plot image with line of best fit on the plot
dlinn [17]

Just take it in co-ordinate pairs

  • (x,y)=(Arm span,Height)

Take two points

  • (58,60)
  • (41,40)

Slope:-

\\ \sf\longmapsto m=\dfrac{40-60}{41-58}

\\ \sf\longmapsto m=\dfrac{-20}{-17}

\\ \sf\longmapsto m=\dfrac{20}{17}

\\ \sf\longmapsto m\approx 1.2

Equation of line in point slope form

\\ \sf\longmapsto y-y_1=m(x-x_1)

\\ \sf\longmapsto y-60=1.2(x-58)

\\ \sf\longmapsto y-60=1.2x-69.6

\\ \sf\longmapsto 1.2x-y-9.6=0

  • Convert to slope intercept form y=mx+b

\\ \sf\longmapsto y=1.2x-9.6

Graph attached

7 0
2 years ago
4. Andrés desea embaldosar el piso de su casa que tiene 375 cm de ancho y 435 cm de largo. Calcula la longitud del lado que tend
svetlana [45]

Answer:

Sabemos que el piso es un rectángulo de 435 cm de largo y 375 cm de ancho.

Recordar que para un rectángulo de largo L, y ancho W, el área es:

A = L*W

Entonces el área del piso, será:

A = 435cm*375cm = 163,125 cm^2

Primero, sabemos que se utilizaran baldosas (las cuales son cuadradas) y queremos saber la longitud de lado que tendrían las baldosas.

No tenemos ningún criterio para encontrar este lado, solo que (si queremos usar un número entero de baldosas) el largo L del lado de la baldosa deberá ser un divisor de tanto el ancho como el largo del suelo.

Dicho de otra forma

el largo, 435cm, tiene que ser múltiplo de L

el ancho, 375cm, tiene que ser múltiplo de L.

Por ejemplo, ambos números son múltiplos de 5, entonces podríamos tomar L = 5cm

En este caso, el área de cada baldosa es:

a = L^2 = 5cm*5cm = 25cm^2

Y el número total de baldosas que necesitaría usar esta dado por el cociente entre el área del suelo y el area de cada baldosa.

N = ( 163,125 cm^2)/(25cm^2) = 6,525 baldosas.

También sabemos que ambos números (435cm y 375cm) son múltiplos de 15cm

Entonces las baldosas podrían tener 15cm de lado.

En este caso, el área de cada baldosa es:

A = (15cm)^2 = 225cm

En este caso el número total de baldosas necesarias será:

N =  ( 163,125 cm^2)/(225cm^2) = 725 baldosas.

5 0
3 years ago
Which inequality models this problem?
lana [24]

Answer:

C

Step-by-step explanation:

$6500 is a one time purchase so there is no variable attached.

$550 and $900 per week is reoccurring so there will be a variable attached.

Since $900 is what she is making each week, this will be separate from her costs (can eliminate D).

To make a profit, her amount earned will need to be greater than her expenses, so the answer is C.

8 0
3 years ago
"3. When we have two sorted lists of numbers in non-descending order, and we need to merge them into one sorted list, we can sim
iren [92.7K]

Answer:

Since we extract n elements in total, the algorithm for the running time for K sorted list is O (n log k+ k) = O (n log k)

Step-by-step explanation:

To understand better how we arrived at the aforementioned algorithm, we take it step by step

a, Construct a min-heap of the minimum elements from each of "k" lists.

The creation of this min-heap will cost O (k) time.

b) Next we run delete Minimum and move the minimum element to the output array.

Each extraction takes O (log k) time.

c) Then insert into the heap the next element from the list from which the element was extracted.

Now, we note that  since we extract n elements in total, the running time is

O (n log k+ k) = O (n log k).

So we can conclude that :

Since we extract n elements in total, the algorithm for the running time for K sorted list is O (n log k+ k) = O (n log k)

5 0
3 years ago
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