For this case we have the following inequality:
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To find the solution we follow the steps below:
We apply distributive property on the right side of inequality:

Adding 13 to both sides of the inequality we have:

We subtract 6x on both sides of the inequality:

Thus, we have that any value of "x" makes the inequality fulfilled. Thus, the solution is given by all real numbers.
Answer:
The solution set is (-∞,∞)
Answer:
Point S coordinates= (-4,5)
Step-by-step explanation:
If you would just move the point 5 PLACES TO THE RIGHT, you would get -4, 5, which is the correct answer.
Notice that
11/12 = 1/6 + 3/4
so that
tan(11π/12) = tan(π/6 + 3π/4)
Then recalling that
sin(x + y) = sin(x) cos(y) + cos(x) sin(y)
cos(x + y) = cos(x) cos(y) - sin(x) sin(y)
⇒ tan(x + y) = (tan(x) + tan(y))/(1 - tan(x) tan(y))
it follows that
tan(11π/12) = (tan(π/6) + tan(3π/4))/(1 - tan(π/6) tan(3π/4))
tan(11π/12) = (1/√3 - 1)/(1 + 1/√3)
tan(11π/12) = (1 - √3)/(√3 + 1)
tan(11π/12) = - (√3 - 1)²/((√3 + 1) (√3 - 1))
tan(11π/12) = - (4 - 2√3)/2
tan(11π/12) = - (2 - √3) … … … [A]
$8,175
you may have to work it out if the numbers are different but this should be the correct answer
This is a bit harder. I suggest getting the Domain and Range for the function of x.
If any of these answers have, an infinite domain and (3, infinite) range. That will be your answer.
Your answer is B.
f(x) = 2x²+3 has the same domain and range as x²+3