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ollegr [7]
2 years ago
10

6) Determine the dimensions of a rectangle if: A = x2 – 19x – 90

Mathematics
1 answer:
Sunny_sXe [5.5K]2 years ago
4 0

Answer:

Step-by-step explanation:

Determine the dimensions of a rectangle if:

A = x2 – 19x – 90

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PLEASE HELP PICTURE IS SHOWN
chubhunter [2.5K]
A because 5*4 = 20 that why its a
6 0
3 years ago
Solve the following equation: 6x - 3x + 13 = 7 + 9x - 6
Colt1911 [192]

Answer:

x = 2

Step-by-step explanation:

3 0
3 years ago
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Lines AB and BC intersect at point B. Ray BD bisects angle ABC. (4x-24) B (x+6) What is the value of x?
Verizon [17]

If line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23

The line AB and BC are intersecting at point B.

Ray BD bisect the  angle ABC

∠ABD = x+8 degrees

∠ABD=∠DBC = x+8

Because the ray BD bisect the ∠ABC, so ∠ABD and ∠DBC will be equal

∠ABD+∠DBC= 4x-30 degrees

Because both are vertically opposite angles

Substitute the values in the equation

x+8 + x+8 = 4x-30

2x+16 = 4x-30

2x-4x = -30-16

-2x = -46

x = 23

Hence, if line AB and BC are intersecting at point B and ray BD bisect  the angle ABC, then the value of x is 23

The complete question is

Line AB and BC are intersecting at point B and ray BD bisect the angle ABC. What is the value of x?

Learn more about angle here

brainly.com/question/28451077

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4 0
1 year ago
Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

5 0
3 years ago
Which expression represents the following statement: x is no less than 0. x>0 x≤0 x≥0 x<0
ki77a [65]

Answer: x ≥ 0

Step-by-step explanation:

First, let's define the symbols used:

a < x              (this means that a is strictly smaller than x)

a > x              (this means that a is strictly larger than x)

a ≤ x              (this means that a is smaller than or equal to x)

a ≥ x              (this means that a is larger than or equal to x)

Now we have the statement "x is no less than 0"

Then x can be equal to zero, or larger than zero, but never smaller than zero.

Looking at the symbols above, we know that we need to use:

x ≥ 0

(this is equivalent to the statement)

7 0
3 years ago
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