Now, find the point where these two lines meet—that is the point with ... We just used them to help us locate the point \left(1,3\right) . ... Since x=2 , the point is to the right of the y-axis. Since y=-3 , the point is below the x-axis. ... Can you tell just by looking at the coordinates in which quadrant the point \left(-2 ... \left(3,-3\right)
