Answer:
ayo so um... i have the same test and uh im taking it rn and i was wonderering if u could give me the answer
Step-by-step explanati
The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:

Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Answer:
350 miles
Step-by-step explanation:
Let x represent the miles driven
The cost with the first plan will be represented by 0.40x + 70
The second plan will be represented by 0.60x
Set these 2 expressions equal to each other and solve for x:
0.40x + 70 = 0.60x
70 = 0.20x
350 = x
So, Susan will have to drive 350 miles for the cost to be the same
Answer:
p = 2
Step-by-step explanation:
p + 4/p - 4
multiplying through by p,
p×p + 4/p ×p - 4×p
p² + 4 - 4p = 0
p² - 4p + 4 = 0
factorizing,
p(p - 2) -2(p - 2) =0
(p -2)(p -2) =0
p-2 =0
p=2
Answer:
Less than. <
Step-by-step explanation: