So this is trig, and when it comes to right (90°) triangles, it's imperative that you know:
SOH-CAH-TOA
Sine (x) = Opposite/Hypotenuse
Cosine (x) = Adjacent/Hypotenuse
Tangent (x) = Opposite/Adjacent
*hypotenuse is always the largest side, and the one opposite the 90° angle in right triangles
therefore we'll use SOH, because the opposite of x (O) and the hypotenuse (H) are given:
Sine (x) = Opposite/Hypotenuse
Sine (x) = 32/58 = 16/29 = 0.552
Sine (x) = 0.552
now we use something called arc-sine, or

it's basically a fancy function of most advanced calculators, so we'll plug it in as:

x = 33.49° --> answer B) is correct
There would be four zeros because 6×5=30, and 10 to the 3rd power would be 1000, and 30×1000=30000, which has four zeros.
Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
The range of the given function is equal to (2, 7).
<h3>What is a range?</h3>
A range can be defined as the set of all real numbers that connects with the elements of a domain. This ultimately implies that, a range refers to the set of all possible output numerical values, which are shown on the y-axis of a graph.
<h3>How to identify the range and domain of this graph?</h3>
The vertical extent of a graph represents all range values and they are always read and written from smaller to larger numerical values, and from the bottom of the graph to the top.
Similarly, the horizontal extent of a graph represents all domain values and they are also read and written from smaller to larger numerical values, and from the left of the graph to the right.
By critically observing the graph of function f(x) shown, we can infer and logically deduce the following:
Range = (2, ∞).
Read more on range here: brainly.com/question/17295757
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Answer:
23.20°
Step-by-step explanation:
All three sides of this right triangle are given, so the acute angle of interest can be found using any of the inverse trig functions.
<h3>Trig relation</h3>
The tangent of the angle is the ratio of opposite and adjacent sides:
Tan = Opposite/Adjacent
Here, that means ...
tan(α) = 3/7
To find the value of α, we need to use the inverse tangent function, also called the arctangent function.
α = arctan(3/7) ≈ 23.19859°
α≈ 23.20°