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Tomtit [17]
3 years ago
14

Answer ASAP, please..

Mathematics
1 answer:
Phantasy [73]3 years ago
6 0

Answer:

g(x) = (x-3)^{2} -4

Step-by-step explanation:

The graph is shifted 3 units to the right which is represented by -3 (in the parentheses) and is shifted four units down.

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Jonathan deposited $20 in a savings account earning 5% interest, compounded annually.
Semenov [28]

Answer:

12$

Step-by-step explanation:

3 0
3 years ago
Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e
Bingel [31]
Assuming the series is

\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}

The series will converge if

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|

We have

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|

So the series will certainly converge if -1, but we also need to check the endpoints of the interval.

If x=1, then the series is a scaled harmonic series, which we know diverges.

On the other hand, if x=-1, by the alternating series test we can show that the series converges, since

\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0

and is strictly decreasing.

So, the interval of convergence for the series is -1\le x.
6 0
3 years ago
Look at the picture you will know<br><br> Please helpppp need it by May 23 2022
Annette [7]
Hey sorry I can’t see the question I see the graph though
3 0
2 years ago
What is the first step in evaluating the expression shown below?<br> (12.9-3.1) 6.2-2 + 43
Nata [24]

Answer:

Subtract 3.1 from 12.9

Hope it helped

3 0
3 years ago
Given the mean 71.4 and sample standard deviation 11.5 what is the z-
Elenna [48]

Answer: 1.18

Step-by-step explanation:

Z = (x - mean) / standard deviation

Z = (85 - 71.4) / 11.5

Z = 13.6 / 11.5 = 1.18

6 0
3 years ago
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