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lana66690 [7]
3 years ago
12

PLEASE HELP, MATH, PLEASESolve for n: n+5/16 = -1​

Mathematics
1 answer:
Anit [1.1K]3 years ago
3 0

\tt Step-by-step~explanation:

To solve for n, we have to isolate n. To do so, we move all the terms that are not n to one side of the equation, and leave n on the other side.

\tt Steps:

Equation: n + 5/16 = -1

Subtract 5/16 on both sides to bring it to the right side of the equation.

\tt n+5/16-5/16=-1-5/16\\\\n=-\frac{21}{16}~or~-1\frac{5}{16}

\Large\boxed{\tt Our~final~answer:~n=-\frac{21}{16}~or~-1\frac{5}{16} }

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Artyom0805 [142]

Answer:

Given f(x) and g(x), please find (fog)(X) and (gof)(x) f(x) = 2x   g(x) = x+3    

Given f(x) and g(x), please find (fog)(X) and (gof)(x)

f(x) = 2x   g(x) = x+3    

print Print document PDF list Cite

Quick Answer

(fog)(x) = 2x + 6

(gof)(x) = 2x + 3

Expert Answers

HALA718 eNotes educator| CERTIFIED EDUCATOR

f(x) = 2x

g(x) = x + 3

First let us find (fog)(x)

(fog)(x) = f(g(x)

            = f(x+3)

              = 2(x+3)

              = 2x + 6

==> (fog)(x) = 2x + 6

Now let us find (gof)(x):

(gof)(x) = g(f(x)

           = g(2x)

          = 2x + 3

==> (gof)(x) = 2x + 3

Step-by-step explanation:


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Step-by-step explanation:

<u>Given:</u>

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In the plane z=2, we have

2 = 4 - x^2 - y^2 \implies x^2 + y^2 = 2 = \left(\sqrt2\right)^2

which is a circle with radius \sqrt2. Then we can better describe the solid by

R = \left\{(x,y,z) ~:~ 0 \le x \le \sqrt2 \text{ and } 0 \le y \le \sqrt{2 - x^2} \text{ and } 2 \le z \le 4 - x^2 - y^2 \right\}

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\displaystyle \iiint_R dV = \int_0^{\sqrt2} \int_0^{\sqrt{2-x^2}} \int_2^{4-x^2-y^2} dz \, dy \, dx

While doable, it's easier to compute the volume in cylindrical coordinates.

\begin{cases} x = r \cos(\theta) \\ y = r\sin(\theta) \\ z = \zeta \end{cases} \implies \begin{cases}x^2 + y^2 = r^2 \\ dV = r\,dr\,d\theta\,d\zeta\end{cases}

Then we can describe R in cylindrical coordinates by

R = \left\{(r,\theta,\zeta) ~:~ 0 \le r \le \sqrt2 \text{ and } 0 \le \theta \le\dfrac\pi2 \text{ and } 2 \le \zeta \le 4 - r^2\right\}

so that the volume is

\displaystyle \iiint_R dV = \int_0^{\pi/2} \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta \, dr \, d\theta \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta\,dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} r((4 - r^2) - 2) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} (2r-r^3) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \left(\left(\sqrt2\right)^2 - \frac{\left(\sqrt2\right)^4}4\right) = \boxed{\frac\pi2}

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Answer:

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Total ways = 5^5

Total ways = 3125

Therefore, the correct option is C) 5^5

Step-by-step explanation:

John has pairs of red, orange, yellow, blue and green socks.

Which means that John has 5 different colors pairs of socks.

We are asked to find out in how many ways can he wear them over 5 days.

1st Day:

On the first day John has 5 ways to choose from.

2nd Day:

On the second day John has 5×5 ways to choose from.

(Since repetition is allowed)

3rd Day:

On the third day John has 5×5×5 ways to choose from.

4th Day:

On the fourth day John has 5×5×5×5 ways to choose from.

5th Day:

On the fifth day John has 5×5×5×5×5 ways to choose from.

Total ways = 5×5×5×5×5

Total ways = 5^5

Total ways = 3125

Therefore, the correct option is C) 5^5

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3 years ago
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