<em><u>Question:</u></em>
Marty and Ethan both wrote a function, but in different ways.
Marty
y+3=1/3(x+9)
Ethan
x y
-4 9.2
-2 9.6
0 10
2 10.4
Whose function has the larger slope?
1. Marty’s with a slope of 2/3
2. Ethan’s with a slope of 2/5
3. Marty’s with a slope of 1/3
4. Ethan’s with a slope of 1/5
<em><u>Answer:</u></em>
Marty’s with a slope of 1/3 has the larger slope
<em><u>Solution:</u></em>
<em><u>Given that Marty equation is:</u></em>

<em><u>The point slope form is given as:</u></em>

Where, "m" is the slope of line
On comapring both equations,

<em><u>Ethan wrote a function:</u></em>
Consider any two values from the table we have;
(0, 10) and (2, 10.4)
<em><u>The slope is given by formula:</u></em>

From above two points,

Therefore,

Thus we get,

Therefore, Marty’s with a slope of 1/3 has the larger slope