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3 years ago

Which absolute value expression represents the distance between the points shown on the number line?

Mathematics

1 answer:

stich3 [128]3 years ago

3 0

Answer:

We will take option B.

Step-by-step explanation:

Option A) |4 − 1| = 3 units

Option B) |4 − (−1)| = 5 units

Option C) |−4 + (−1)| = 5 units

Option D) |−4 − (−1)| = 3 units.

Now, from the number line and from the points given on the number line it is clear that the distance from one point to another is 5 units.

So. option B or Option C can be the right one.

Now, the right side point is on +4 point and the left side point is on -1 point.

So, the distance between those points will be calculated as 4 - (- 1) = 5.

Therefore, we will take option B. (Answer)

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A jet plane has a takeoff speed of vto = 75 m/s and can move along the runway at an average acceleration of 1.3 m/s2. If the len

pishuonlain [190]

Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m

time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s

the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s

Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.

6 0

3 years ago

Read 2 more answers

Simplify the expression: (a/b)^k

PilotLPTM [1.2K]

Answer:

A^k/b^k

Step-by-step explanation:

A/b^k=a^k/b^k

3 0

3 years ago

What is 4n + 3 ( n – 5 ) + 2 simplified? I suck At math sry

Tema [17]

Answer:

$7n−13$

Step-by-step explanation:

$4n+3(n−5)+2$

$4n+3n+3 \times (−5+2)$

$4n+3n−15+2$

$7n−15+27n-15+2$

$7n−13$

<h3>Hope it is helpful....</h3>

4 0

2 years ago

Read 2 more answers

Describe the transformation in the figure below

Keith_Richards [23]

Answer:

A) Reflection.

Step-by-step explanation:

From the figure shown, we can see that the blue triangle is flipped about the x-axis to form the red triangle.

When an object is flipped about a line, then this transformation is called reflection about that line.

Thus, we can say that reflection is taking place in the figure shown in which the x-axis is acting like a mirror. The blue triangle is the pre-image and the red triangle is the image after reflection.

The reflection about x-axis is given by:

$Pre-image(x,y)\rightarrow Image(x,-y)$