Answer:
D, (1,2)
Step-by-step explanation:
It all comes down to substitution. In this case the coefficient of x is 3 and the coefficient of y is 4. The format of these coordinates being (x,y).
1. Plug in your x value (1 in this circumstance) and solve:
3(1) + 4y < 12
3 + 4y < 12
2. Plug in your y value (2 in this circumstance) and solve:
3 + 4(2) < 12
3 + 8 < 12
3. Solve
3 + 8 = 11
11 < 12
Hello!
I would say the correct answer is C. BF
The definition of a radius is "<span>a straight line from the center to the circumference of a circle or sphere."
I hope this helps :)</span>
Answer: x = 1 and y = 2
Given:
y = -3x + 5
5x - 4y = -3
Since we are given y, let’s sub it in the second equation.
5x - 4(-3x + 5) = -3
5x + 12x - 20 = -3
17x = 17
x = 1
After finding x, we can now find y.
5(1) - 4y = -3
-4y = -8
y = 2
Checking:
y = -3x + 5
2 = -3(1) + 5
2 = 2
5x - 4y = -3
5(1) - 4(2) = -3
-3 = -3
Answer:
d) XY > RS
Step-by-step explanation:
When comparing triangles, the angle opposite to the side in question determines the length. In this case 99 is greater than 75. Since XY is the side opposite to 99, it is the larger side
Answer:
Q13. y = sin(2x – π/2); y = - 2cos2x
Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1
Step-by-step explanation:
Question 13
(A) Sine function
y = a sin[b(x - h)] + k
y = a sin(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Phase shift = π/2.
2h =π/2
h = π/4
The equation is
y = sin[2(x – π/4)} or
y = sin(2x – π/2)
B. Cosine function
y = a cos[b(x - h)] + k
y = a cos(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Reflected across x-axis, y ⟶ -y
The equation is y = - 2cos2x
Question 14
(A) Sine function
(1) Amp = 2; a = 2
(2) Shifted down 1; k = -1
(3) Per = π; b = 2
(4) Phase shift = 0; h = 0
The equation is y = 2sin2x -1
(B) Cosine function
a = 2, b = -1; b = 2
Phase shift = π/2; h = π/4
The equation is
y = -2cos[2(x – π/4)] – 1 or
y = -2cos(2x – π/2) - 1
