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vitfil [10]
3 years ago
12

Please help me with these 2

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
8 0

Okay, so I posted the answer to the first one already :)) aaaand the second one, in order of blanks, should beeeee

3, 1

100, 1000

30, 1

:) I hope it makes sense!!

hammer [34]3 years ago
5 0

\bf ~\hspace{10em}0.031
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\boxed{3}\times \cfrac{1}{100}+\boxed{1}\times \cfrac{1}{1000}\implies \cfrac{3}{100} + \cfrac{1}{100}
\\\\\\
\stackrel{\textit{added 0 to top/bottom}}{\cfrac{30}{1000}}+\cfrac{1}{1000}\implies \cfrac{31}{1000}

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4 years ago
State weather the following can be expressed as a ratio 12g and 45kg
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Find the slope of the tangent line of the curve r = cos (3theta) at theta = pi / 3
LiRa [457]

The slope of the tangent line to the curve at a point <em>(x, y)</em> is d<em>y</em>/d<em>x</em>. By the chain rule, this is equivalent to

d<em>y</em>/d<em>θ</em> × d<em>θ</em>/d<em>x</em> = (d<em>y</em>/d<em>θ</em>) / (d<em>x</em>/d<em>θ</em>)

where <em>y</em> = <em>r(θ)</em> sin(<em>θ</em>) and <em>x</em> = <em>r(θ)</em> cos(<em>θ</em>). Then

d<em>y</em>/d<em>θ</em> = d<em>r</em>/d<em>θ</em> sin(<em>θ</em>) + <em>r(θ)</em> cos(<em>θ</em>)

d<em>x</em>/d<em>θ</em> = d<em>r</em>/d<em>θ</em> cos(<em>θ</em>) - <em>r(θ)</em> sin(<em>θ</em>)

Given <em>r(θ)</em> = cos(3<em>θ</em>), we have

d<em>r</em>/d<em>θ</em> = -3 sin(3<em>θ</em>)

and so

d<em>y</em>/d<em>x</em> = (-3 sin(3<em>θ</em>) sin(<em>θ</em>) + cos(3<em>θ</em>) cos(<em>θ</em>)) / (-3 sin(3<em>θ</em>) cos(<em>θ</em>) - cos(3<em>θ</em>) sin(<em>θ</em>))

When <em>θ</em> = <em>π</em>/3, we end up with a slope of

d<em>y</em>/d<em>x</em> = (-3 sin(<em>π</em>) sin(<em>π</em>/3) + cos(<em>π</em>) cos(<em>π</em>/3)) / (-3 sin(<em>π</em>) cos(<em>π</em>/3) - cos(<em>π</em>) sin(<em>π</em>/3))

d<em>y</em>/d<em>x</em> = -cos(<em>π</em>/3) / sin(<em>π</em>/3)

d<em>y</em>/d<em>x</em> = -cot(<em>π</em>/3) = -1/√3

4 0
3 years ago
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