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Vlada [557]
2 years ago
13

The area of a rectangle is represented by x^2- 7x + 10. What are the missing side lengths of the rectangle?

Mathematics
1 answer:
ladessa [460]2 years ago
4 0
Length = x - 2
Width = x - 5

Explanation:

Area = x^2 - 7x + 10
Area = (x - 2)(x - 5)
Area = Length x Width

Length = x - 2
Width = x - 5
You might be interested in
What numerical expression is equivalent to (2^2)^3
oksian1 [2.3K]

Answer:2*2=4

4^3=4*4*4=64

Step-by-step explanation:

5 0
2 years ago
What is the area of a triangle with a base of 50 feet and a height of 75 feet’
inysia [295]

Answer:

The correct answer is,

the area of given triangle = 1875 square feet

Step-by-step explanation:

Formula:

Area of triangle = bh/2

b - Base and h - height

It is given that,a triangle with a base of 50 feet and a height of 75 feet’

<u>To find the area of triangle</u>

base b = 50 feet and height h = 75 feet

Area = bh/2 = (50 x 75 )/2

Area = 3750/2 = 1875 square feet

Therefore the area of given triangle = 1875 square feet

8 0
3 years ago
Read 2 more answers
Bad at math... help please ):
zavuch27 [327]
Smallest side XYZ/ Smallest side ABC = Longest side XYZ/ Longest side ABC
Let longest side XYZ be x
280/112 = x/144
x = (280/112)×144
x = 360
Option D will be your answer

Hope it helped!
3 0
3 years ago
This is Matrix for pre calc
gavmur [86]

The given system of equations in augmented matrix form is

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]

If you need to solve this, first get the matrix in RREF:

  • Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]

  • Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]

  • Add 164(row 3) to -91(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]

  • Multiply row 4 by 1/13080:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]

  • Add -153(row 4) to row 3:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]

  • Multiply row 3 by -1/91:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Add 6(row 3) and -8(row 4) to row 2:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Multiply row 2 by 1/5:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Multiply row 1 by 1/3:

\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

So the solution to this system is (w,x,y,z)=(1,-2,4,-3).

6 0
3 years ago
PLS HELP! NO GUESSING<br><br> 5r + r3s<br><br> IS IT A MONOMIAL YES OR NO EXPLAIN ANSWER
Natalka [10]
Nope, <span>5r + r3s is not a monomial. 
Monomials cannot include addition or subtraction, and since this uses addition, it is not a monomial. 
</span>

I hope this helps and have a great day! If you need anymore help you can link me to another question and I will try to solve it!

6 0
3 years ago
Read 2 more answers
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