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klemol [59]
3 years ago
7

Identify the terms. Then identify the coefficients of the variable terms of the expression. (Enter your answers as a comma-separ

ated list.)
5√3x^2+4
Mathematics
1 answer:
tino4ka555 [31]3 years ago
7 0

Answer:

The set of coefficients asociated with the given polynomial in ascending order is [C] = \{4,0,5\sqrt{3}\}.

Step-by-step explanation:

Let y = 5\sqrt{3}\cdot x^{2}+4, which is a polynomic function, defined as:

y = \Sigma_{i=0}^{n}c_{i}\cdot x^{i} (1)

Where:

c_{i} - i-th Coefficient.

x^{i} - i-th Power.

n - Grade of the polynomial.

We notice that given polynomial has degree 2 and can be rewritten by applying this definition:

y = 4 + 0\cdot x + 5\sqrt{3}\cdot x^{2}

Then, the set of coefficients asociated with the given polynomial in ascending order is:

[C] = \{4,0,5\sqrt{3}\}

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1/3 (6x +12) - 2(x-7)=19
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Answer:

no solution

Step-by-step explanation:

Given

\frac{1}{3}(6x + 12) - 2(x - 7) = 19 ← distribute parenthesis on left side

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4 0
3 years ago
What is the distance between coordinates (-6.25,5) and (-3.75,2)
Oksi-84 [34.3K]

Answer:

\sqrt{15.25}

Step-by-step explanation:

To find the distance, we can use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} when the given points are (x_1,y_1) and (x_2,y_2)

Plug in the points (-6.25,5) and (-3.75,2)

d=\sqrt{(-6.25-x_1)^2+(5-y_1)^2}\\d=\sqrt{(-6.25-(-3.75))^2+(5-2)^2}\\d=\sqrt{(-6.25+3.75)^2+(5-2)^2}\\d=\sqrt{(-2.5)^2+(3)^2}\\d=\sqrt{6.25+9}\\d=\sqrt{15.25}

Therefore, the distance between the two coordinates is \sqrt{15.25}, or approximately 3.91.

I hope this helps!

6 0
2 years ago
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