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Alecsey [184]
3 years ago
8

A logistics company's vulnerability scan identifies the following vulnerabilities on Internet-facing devices in

Computers and Technology
1 answer:
icang [17]3 years ago
8 0

Answer:

A. Microsoft Office Remote Code Execution

Explanation:

From the given options, we have;

The web server having a SQL injection is infrequently use

The information on the website having SSL/TLS not used is promotional

The location of the server having  a TLS downgrade is on a development network

The location of the Microsoft Office Remote Code Execution is on a human resource system test server

Therefore, given that the test server, is the deployment source of the main server, and that with a Remote Code Execution, RCE,  cyber attack, the attacker is able to make commands work on other computers, the RCE attack on the test server is a potential access of an attack on the main servers, and should be patched first.

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What two statements about IPv6 addresses are true? This task contains the radio buttons and checkboxes for options. The shortcut
Oliga [24]

Answer:

A and C

Explanation:

Option A:

In IPv6 there is a rule to reduce an IPv6 address when there are two or more consecutive segments of zeros just one time. This rule says that you can change the consecutive zeros for “::”  

Here is an example

How to reduce the following IPv6 address?

ff02:0000:0000:0000:0000:0000:0000:d500

Ans: ff02::d500

Example 2:

2001:ed02:0000:0000:cf14:0000:0000:de95

Incorrect Answer -> 2001:ed02::cf14::de95  

Since the rule says that you can apply “::” just one time, you need to do it for a per of zero segments, so the correct answer is:

Correct Answer -> 2001:ed02::cf14:0:0:de95

Or

2001:ed02:0:0:cf14::de95

Option C:

Since in IPv6 there are 2^{128} available addresses which means 340.282.366.920.938.463.463.374.607.431.768.211.456 (too many addresses), there is no need of NAT solution, so each device can have its own IP address by the same interface to have access through the internet if needed. If not, you can block the access through internet by the firewall.

4 0
3 years ago
Which is a sentence fragment?
ehidna [41]
C is a sentence fragment it does not have a verb
5 0
3 years ago
Given three floating-point numbers x, y, and z, output x to the power of z, x to the power of (y to the power of z), the absolut
STALIN [3.7K]

Solution :

x = float_(input())

y = float_(input())

z = float_(input())

res1 = x**z

res2 = x**(y**z)

res3 = abs(x-y)

res4 = (x**z)**0.5

print('{:.2f} {:.2f} {:.2f} {:.2f}'.format(res1,res2,res3,res4))

Output is :

5.0

1.5

3.2

172.47 361.66 3.50 13.13

6 0
3 years ago
Consider the code fragment below (with nested loops). int sum = 0;for (int i = 1; i < 5; i++) for (int j = 1; j <= i; j++)
sammy [17]

Answer:

Option d is the correct answer for the above question.

Explanation:

  • The first loop of the program has a second loop and then the statement. In this scenario, the second loop executes for the value of the first loop and the statement executes for the value of the second loop.
  • The first loop executes 4 times, Then the second loop or inner loop executes n times for the n iteration of the first loop, for example, 1 time for the first iteration of the first loop, 2 times for the second iteration of the first loop and so on.
  • Then the inner loop executes (1+2+3+4) iteration which gives the result 10 iterations.
  • The sum initial value is 0 and the "sum++", increase the value of the sum by 1.
  • So the value of the sum becomes 10 after completing 10 iterations of the inner for loop.
  • Hence the 10 will be the output. So the Option d is the correct answer while the other is not.
3 0
3 years ago
Explain demand paging with a proper example
julia-pushkina [17]
<h2><em><u>Demand</u></em><em><u> </u></em><em><u>paging</u></em><em><u> </u></em><em><u>:</u></em></h2>

<h3><em>In computer operating systems, demand paging (as opposed to anticipatory paging) is a method of virtual memory management. In a system that uses demand paging, the operating system copies a disk page into physical memory only if an attempt is made to access it and that page is not already in memory (i.e., if a page fault occurs). It follows that a process begins execution with none of its pages in physical memory, and many page faults will occur until most of a process's working set of pages are located in physical memory. This is an example of a lazy loading technique.</em></h3>

<h3 />

6 0
3 years ago
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