Let's go through the answer choices to see which are true or which are false.
To help us out, we'll use the graph which I've posted below (attached image).
Choice A is true because plugging t = 0 into the function leads to h = 6. The graph shows the y intercept is 6. This is where the ball starts.
Choice B is false. The graph shows two x intercepts, but the negative root isn't useful (we cannot have a negative time value). So we really only have one useful root. This is where the ball hits the ground.
Choice C is false. It's actually the other way around, where h increases first, then decreases. In other words, the ball goes up before it comes back down (instead of going down first and then popping back up). Refer to the graph below.
Choice D is true. Refer to the graph below. We can determine this in a non-visual way by noticing the leading term -16t^2 has a negative coefficient. A negative leading coefficient means the parabola opens downward to produce a highest point at the vertex.
Choice E is false. This contradicts choice which was shown to be true.
Choice F is true. The -16 refers to half of 32 ft/s^2, which is the acceleration of gravity. This value is approximate. Having an acceleration of 32 ft/s^2 means the ball's speed increases by 32 ft/s for each second.
The effective annual interest rate is: i = (1 + 0.064/12)^12 - 1 = 0.066 In year 1: the interest is $613.80 (multiple $9300 by 0.066) In year 2: the interest is $654.31 (add interest from year 1 to $9300 and multiply by 0.066) In year 3: the interest is $656.98 (do the same as year 2) In year 4: the interest is $657.16
The total interest is: $2582.25 The present worth of this amount is: P = 2582.23 / (1 + 0.066)^4 = $1999.72