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kari74 [83]
2 years ago
5

Please help I would appreciate it

Mathematics
1 answer:
puteri [66]2 years ago
5 0

Answer:

B. 95

Step-by-step explanation:

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This 2 pls i need help with explanation sum
Nataliya [291]

9514 1404 393

Explanation:

<h3>8.</h3>

An exterior angle is equal to the sum of the remote interior angles. Define ∠PQR = 2q, and ∠QPR = 2p. The purpose of this is to let us use a single character to represent the angle, instead of 4 characters.

The above relation tells us ...

  ∠PRS = ∠PQR +∠QPR = 2q +2p

Then ...

  ∠TRS = (1/2)∠PRS = (1/2)(2q +2p) = q +p

and

  ∠TRS = ∠TQR +∠QTR . . . . . exterior is sum of remote interior

  q +p = (1/2)(2q) +∠QTR . . . . substitute for ∠TRS and ∠TQR

  p = ∠QTR = 1/2(∠QPR) . . . . . subtract q

__

<h3>9.</h3>

For triangle ABC, draw line DE parallel to BC through point A. Put point D on the same side of point A that point B is on the side of the median from vertex A. Then we have congruent alternate interior angles DAB and ABC, as well as EAC and ACB. The angle sum theorem tells you that ...

  ∠DAB +∠BAC +∠CAE = ∠DAE . . . . a straight angle = 180°

Substituting the congruent angles, this gives ...

  ∠ABC +∠BAC +∠ACB = 180° . . . . . the desired relation

4 0
3 years ago
Apply the distribution property to produce an equivalent expression 2(7g + 7)
ira [324]
21+g or it could be(still the same thing) 21 + 1g
3 0
3 years ago
Answer with work plssss
Inessa05 [86]

Answer:

2a^4b^6

Step-by-step explanation:

a^2(ab^3)^2+b^2(a^2b^2)^2\\\\=a^2(a^2b^{2*3})+b^2(a^{2*2}b^{2*2})\\\\=a^2(a^2b^6)+b^2(a^4b^4)\\\\=a^{2+2}b^6+a^4b^{4+2}\\\\=a^4b^6+a^4b^6\\\\=2a^4b^6

6 0
3 years ago
Please show your work
Paladinen [302]

Answer:

see in the picture, the perimeter of this rectangle is

2( x + 3x) = 8x but the perimeter is 65.6

=> 8x = 65.6

<=> x = 65.6/8

=> x = 8.2

7 0
3 years ago
What is the domain of f(x)=3^x
zimovet [89]

Answer:

B

Step-by-step explanation:

This is an exponential function. These types of functions have asymtotes. Asymtotes are when x or y is approaching a specific value, but it's not touching it. If you put your function in a graphing calculator, you will find that the y is approaching 0, but it's not quite touching it. What we're looking for, however is domain (x), and there are no asymtotes for x because as you can see, every value on the x axis has a y point. Therefore the domain is all real numbers.

7 0
3 years ago
Read 2 more answers
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