When you multiply powers, they add, and when you divide them they subtract.
So I would first add the 2^a + 2^b +2^c to get 2^(a+b+c)
Then, divide by 2^(a+b). Because when you divide powers they subtract, you will be taking away the (a+b) from the (a+b+c) and you will be left with c on its own.
The answer is 2^c
Answer:
<h2>-8</h2>
Step-by-step explanation:
![4-3[6-2(4-3)]\\\\Follow\:the\:PEMDAS\:order\:of\:operations\\\\\mathrm{Calculate\:within\:parentheses}\:\left[6-2\left(4-3\right)\right] : 4\\\\=4-3\times\:4\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:3\times\:4\::\quad 12\\=4-12\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:4-12\:\\\\:\quad -8](https://tex.z-dn.net/?f=4-3%5B6-2%284-3%29%5D%5C%5C%5C%5CFollow%5C%3Athe%5C%3APEMDAS%5C%3Aorder%5C%3Aof%5C%3Aoperations%5C%5C%5C%5C%5Cmathrm%7BCalculate%5C%3Awithin%5C%3Aparentheses%7D%5C%3A%5Cleft%5B6-2%5Cleft%284-3%5Cright%29%5Cright%5D%20%3A%204%5C%5C%5C%5C%3D4-3%5Ctimes%5C%3A4%5C%5C%5C%5C%5Cmathrm%7BMultiply%5C%3Aand%5C%3Adivide%5C%3A%5Cleft%28left%5C%3Ato%5C%3Aright%5Cright%29%7D%5C%3A3%5Ctimes%5C%3A4%5C%3A%3A%5Cquad%2012%5C%5C%3D4-12%5C%5C%5C%5C%5Cmathrm%7BAdd%5C%3Aand%5C%3Asubtract%5C%3A%5Cleft%28left%5C%3Ato%5C%3Aright%5Cright%29%7D%5C%3A4-12%5C%3A%5C%5C%5C%5C%3A%5Cquad%20-8)
6 1/4 :) Is this correct?
Answer:
option 1 is true. -1/2=-0.5
