Function 1 is a constant function
.. y = 2
Function 2 has the value 3 at x=0.
3 is greater than 2, so Function 2 has the greater initial value.
<h3>
Answer: a^2 - b^2 = (a-b)(a+b)</h3>
The order of the factors does not matter.
So (a-b)(a+b) is the same as (a+b)(a-b)
This is known as the difference of squares factoring rule.
You can FOIL out (a-b)(a+b) and you'd get a^2+ab-ab-b^2. Note how the ab terms cancel leaving us with a^2-b^2. This confirms we have the correct factorization.
We can’t attach imagines on here
Answer:
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Step-by-step explanation:
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Answer:
y = 2x - 3
Step-by-step explanation:
Take any tow point from the line
(x₁ , y₁) = (1 , -1) & (x₂ , y₂) = (0 , -3)
![= \frac{-3-[-1]}{0-1}\\\\=\frac{-3+1}{-1}\\\\=\frac{-2}{-1}\\\\=2](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B-3-%5B-1%5D%7D%7B0-1%7D%5C%5C%5C%5C%3D%5Cfrac%7B-3%2B1%7D%7B-1%7D%5C%5C%5C%5C%3D%5Cfrac%7B-2%7D%7B-1%7D%5C%5C%5C%5C%3D2)
m = 2 & (1, -1)
y - y₁ = m(x -x₁)
y - [-1] = 2(x - 1)
y + 1 = 2x - 2
y = 2x - 2 - 1
y = 2x - 3
