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My name is Ann [436]
2 years ago
9

Solve the system of equations: 5x + 3y = 23 3y = 15x - 21

Mathematics
1 answer:
Rama09 [41]2 years ago
4 0

Answer:

x=11/5 and y=4

Explanation:

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ANSWER ASAP PLEASE FOR BRAINLIEST
PSYCHO15rus [73]

Answer:

<h2><em><u>11.2 - B to C</u></em></h2><h2><em><u>12 - B to A</u></em></h2><h2><em><u>8.8 - A to C</u></em></h2>

You have to multiply all the sides by 4.

B to C = 2.8*4

2.8 * 4 = 11.2

B to A = 3*4

3*4 = 12

A to C = 2.2*4

2.2*4 = 8.8

Hope this helped!

3 0
3 years ago
I need help with an Algebra question. The question is in the picture. Thank you &lt;3
olchik [2.2K]
The domain is the set of allowed inputs, in this case t values. The smallest t value allowed is t = 0. The largest is t = 165. So that's why the domain is 0 \le t \le 165

-------------------------------

The range is 0 \le H \le 40000 since H = 0 is the smallest output of the function and H = 40,000 is the largest output. Like the domain, the range is the set of possible outputs of a function.

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3 years ago
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Rama09 [41]

Answer:

C

Step-by-step explanation:

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3 years ago
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PLEASE HELP WILL GIVE 10 POINTS. HURRYY
Anvisha [2.4K]

B. -4-1. -4-1=-5, which is the amount of you count the spaces in between.

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2 years ago
Consider a line whose slope is 6 and which passes through the point (8.–2).
Zolol [24]

Answer:

y=6(x-8)-2\qquad\text{point-slope form}

y=6x-50\qquad\text{slope-intercept form}

Step-by-step explanation:

The equation of a line can be written in several forms. Two of the most-used forms are the point-slope and the slope-intercept forms.

The point-slope form requires to have one point (xo, yo) through which the line passes and the slope m. The equation expressed in this form is:

y=m(x-xo)+yo

The slope-intercept form requires to have the slope m and the y-intercept b, or the y-coordinate of the point where the line crosses the y-axis. The equation is:

y=mx+b

The line considered in the question has a slope m=6 and passes through the point (8,-2). These data is enough to find the point-slope form of the line:

\boxed{y=6(x-8)-2\qquad\text{point-slope form}}

To find the slope-intercept form, we operate the above equation:

y=6x-48-2

\boxed{y=6x-50\qquad\text{slope-intercept form}}

3 0
3 years ago
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