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Soloha48 [4]
3 years ago
10

Consider a line whose slope is 6 and which passes through the point (8.–2).

Mathematics
1 answer:
Zolol [24]3 years ago
3 0

Answer:

y=6(x-8)-2\qquad\text{point-slope form}

y=6x-50\qquad\text{slope-intercept form}

Step-by-step explanation:

The equation of a line can be written in several forms. Two of the most-used forms are the point-slope and the slope-intercept forms.

The point-slope form requires to have one point (xo, yo) through which the line passes and the slope m. The equation expressed in this form is:

y=m(x-xo)+yo

The slope-intercept form requires to have the slope m and the y-intercept b, or the y-coordinate of the point where the line crosses the y-axis. The equation is:

y=mx+b

The line considered in the question has a slope m=6 and passes through the point (8,-2). These data is enough to find the point-slope form of the line:

\boxed{y=6(x-8)-2\qquad\text{point-slope form}}

To find the slope-intercept form, we operate the above equation:

y=6x-48-2

\boxed{y=6x-50\qquad\text{slope-intercept form}}

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You're nearly there. Just some more steps.
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