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Nana76 [90]
3 years ago
8

Solve 5.3×0.5 and show work

Mathematics
1 answer:
Inga [223]3 years ago
8 0
5.3 * 0.5 = 2.65
5.3/2=2.65
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Help with this task it's confusing can u explain how you got the answer
Andru [333]
Oh my goodness !  You were doing such an absolutely beautiful job,
as far as you went, but then you ran into some rough road and quit.

You've got the correct expressions for the ages of the three people:

-- Will . . . w
-- Ben . . . w+3
-- Jan . . . 2(w+3)
You slipped up when you expanded Jan's age:  2(w+3) = <u>2w + 6</u> ,
and it was all down hill from there.

Let's do it again, together:

-- Will . . . w
-- Ben . . . w + 3
-- Jan . . . 2w + 6

Total:  (w + w + 2w) + (3 + 6) = 4w + 9

So the equation is:    <em><u>4w + 9 = 41</u></em>
Now you're supposed to solve it.

Subtract 9 from each side:   4w  =  32

Divide each side by 4:        <u>w = 8</u>

-- Will = w . . . . . 8 y.o.
-- Ben = w+3 . . . 11 y.o.
-- Jan = 2(w+3) . . 22 y.o.

When will Jan be twice as old as Will ?
That'll happen in 'x' years.
At that time, Will will be (8+x) and Jan will be (22+x),
and her age will be double Will's age.

22 + x  =  2(8 + x)

22 + x  =  16 + 2x

Subtract 'x' from each side:    22  =  16 + x

Subtract  16  from each side:  <em>  6 = x</em>

<u>Check:</u>

In 6 years, Jan will be (22+6) = 28,
and Will will be (8+6) = 14 .

28 = twice as old as 14.      yay!

Can I make a little suggestion ?
I'm going to make it anyway:

Your problem was neatness.
You were doing great work in that big open space on the sheet, but it
started to get ragged.  When you tried to look back to see if you made
a mistake, you couldn't find it in the mess.
This is not an easy problem, but you definitely know your stuff. 
I think if you keep it a little neater, you're going to sparkle !
7 0
3 years ago
Fill in the blanks to make the solution correct: <br> 5._4 - (_.8_)=-3.61
Triss [41]
5.44-1.83=3.61

  5._4
-_.8_   =

3.61
7 0
3 years ago
A triangular prism is 18 inches long and has a triangular face with a base of 16 inches and a height of 15 inches. The other two
Elenna [48]

Answer: I DONT KNOW

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
PLEASE HELP I NEED IT QUIK<br><br> I need help with b and c putting it on the graph PLEASE HELP
Sergio [31]

Answer:

I cannot see very well can you tell me the answer

Step-by-step explanation:

5 0
3 years ago
The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day 333 people enter the park, the
liberstina [14]

Answer:

<u>188 children</u> and <u>145 adults</u> were admitted in the park.

Step-by-step explanation:

Given:

The admission fee at an amusement park is $1.50 for children and $4 for adults.

Total $862 collected on a certain day when 333 people enter the park.

Now, to find the children and adults admitted in the park.

<u><em>Let the number of children admitted be </em></u>x.<u><em /></u>

<u><em>And the the number of adults admitted be </em></u>y.<u><em /></u>

So, the total people enter the park:

x+y=333\\\\x=333-y\ \ \ ...(1)

Thus, the total amount collected of the admission fee:

1.50(x)+4(y)=862\\\\

Substituting the value of x from equation (1):

1.50(333-y)+4(y)=862\\\\499.50-1.50y+4y=862\\\\499.50+2.50y=862\\\\Subtracting\ both\ sides\ by\ 499.50\ we\ get:\\\\2.50y=362.50\\\\Dividing\ both\ sides\ by\ 2.50\ we\ get:\\\\y=145.

<u><em>Thus, the number of adults = 145.</em></u>

Now, to get the number of children by substituting the value of y in equation (1) we get:

x=333-y\\\\x=333-145\\\\x=188.

<u><em>Hence, the number of children = 188.</em></u>

Therefore, 188 children and 145 adults were admitted in the park.

4 0
4 years ago
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