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Akimi4 [234]
3 years ago
13

Each day, Deanne starts working at 10:00 a.m. and Stephanie starts working at noon. At which time each day are the earnings for

Deanne equal to the earnings for Stephanie?​

Mathematics
1 answer:
dedylja [7]3 years ago
5 0

Answer:

Time when both earnings are equal = 5:00 Pm

Step-by-step explanation:

Given:

Total earning of Deanne = 6.50x

Total earning of Stephanie = 9.10(x -2)

Work started at 10:00 am

Find:

Time when both earnings are equal

Computation:

Total earning of Deanne = Total earning of Stephanie

6.50x = 9.10(x - 2)

6.5x = 9.1(x-2)

6.5x = 9.1x - 18.2

9.1x - 6.5x = 18.2

2.6x = 18.2

x = 18.2 / 2.6

x = 7 hour

So,

Time when both earnings are equal = Work started at 10:00 am + 7 hour

Time when both earnings are equal = 5:00 Pm

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Simplify expression x8y-26/x14y-5 × x-39y-21
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The simplified form of the expression is x^{-45} y^{-42}

<h3>Simplifying an expression</h3>

From the question, we are to simplify the given expression

The given expression is

\frac{x^{8}y^{-26}  }{x^{14}y^{-5}  } \times x^{-39} y^{-21}

The expression can be simplified as shown below

\frac{x^{8}y^{-26}  }{x^{14}y^{-5}  } \times x^{-39} y^{-21}

\frac{x^{8} \times x^{-39} \times  y^{-26} \times  y^{-21}  }{x^{14} \times y^{-5}  }

\frac{x^{8+-39} \times  y^{-26+-21}  }{x^{14} \times y^{-5}  }

\frac{x^{8-39} \times  y^{-26-21}  }{x^{14} \times y^{-5}  }

\frac{x^{-31} \times  y^{-47}  }{x^{14} \times y^{-5}  }

Then,

\frac{x^{-31} }{x^{14} } \times \frac{ y^{-47} }{ y^{-5} }

x^{-31-14} \times y^{-47--5}

x^{-31-14} \times y^{-47+5}

x^{-45} \times y^{-42}

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Hence, the simplified form of the expression is x^{-45} y^{-42}

Learn more on Simplifying an expression here: brainly.com/question/2320607

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<h3>What is a confidence interval?</h3>

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We have:

A survey of 504 citizens found that 378 of them favor a new bill introduced by the city.

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That would get you to 81.6.

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