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kondor19780726 [428]
3 years ago
7

Someone please help it’s dueee today!

Mathematics
1 answer:
OLEGan [10]3 years ago
5 0
Y=6/5x+9/2 I think but I’m pretty sure it’s this one maybe I’m just here for the points
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How many different 3 topping pizzas can be made if 10 different toppings are available?
kicyunya [14]
Assuming you can’t use the same topping twice,
10 x 9 x 8 = 720
3 0
3 years ago
Read 2 more answers
3. Find the surface area of the figure.<br> 9.4 ft<br> 7 ft<br> 11 ft<br> 15 ft<br> 5 ft
mylen [45]

Answer:

use a caculater mabey

Step-by-step explanati

5 0
3 years ago
Anjeli writes the equation (a+b)2=c2+4(12ab) to begin a proof of the Pythagorean theorem.
gavmur [86]

Answer:

Therefore Anjeli is correct and

(a+b)^{2}=c^{2}+4(\frac{1}{2}ab)  is TRUE.

Step-by-step explanation:

Given:

Label on triangle as ΔABC right angle at C such that

AB = c  .....(Hypotenuse)

AC = b  ....(Longer leg)

BC = a  ....(Shorter leg)

To Prove:

(a+b)^{2}=c^{2}+4(\frac{1}{2}ab)

Proof:

We know, in Right angle triangle ABC by Pythagoras theorem we get,

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

Substituting the values we get

AB^{2}=BC^{2}+AC^{2}\\\\c^{2}=a^{2}+b^{2}    ...............( 1 )

Now the Left hand side of what Anjeli wrote is

Left hand side = (a+b)²

 Using identity (A+B)² = A²+ B² + 2AB we get

Left hand side = a²+ b² + 2ab

From ( 1 ) we have c^{2}=a^{2}+b^{2}

Substituting we get

Left hand side = c² + 2ab        ...........................( 2 )

Now,

Right hand side =c^{2}+4(\frac{1}{2}ab)

Dividing 4 by 2 we get  2, hence

Right hand side =c^{2}+2ab  .........................( 3 )

Therefore,

Left hand side = Right hand side          From  ( 2 ) and ( 3 )

(a+b)^{2}=c^{2}+4(\frac{1}{2}ab)      ..True

Therefore Anjeli is correct and

(a+b)^{2}=c^{2}+4(\frac{1}{2}ab)  is TRUE.

7 0
3 years ago
Read 2 more answers
Find the value of x .<br> K<br> M<br> (2x – 10) (2x + 40)º<br> -<br> N
koban [17]

Answer:

?????????????????????????

3 0
3 years ago
Find x - y subtracted from 0.<br> O-X+y<br> О-у-х<br> X-y
frez [133]
I think that it would be 0-x-y
6 0
3 years ago
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