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2 years ago

13

If a plant grew from 6 inches, by 10 inches by, what percent did it increase

1 answer:

Zinaida [17]2 years ago

5 0

I believe it would be 1.667 (1 2/3) percent

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4/5 divided by 1/3 plus 1/5 minus 3/5

r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

as

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

so

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

so

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

so

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

so

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

4 0

2 years ago

Alexandra [31]

The answer is 1.715 hope I helped

4 0

3 years ago

-3/5 x 2/-9 x 8 write your answer in simplest form.

nata0808 [166]

Answer:

16/15

Step-by-step explanation:

$\dfrac{-3}{5}\cdot\dfrac{2}{-9}\cdot 8=\dfrac{3\cdot 2\cdot 8}{5\cdot 9}=\dfrac{2\cdot 8}{5\cdot 3}=\dfrac{16}{15}$

The two minus signs cancel, so the result is positive.

6 0

2 years ago

What is 2× - 5 > or equal to 9

choli [55]

X > or equal to 7 u switch the signs around if you divide or multiply by a negative

4 0

2 years ago

Please help me prove that ED is congruent to BA! I thought I had it right by proving right and vertical angles, but I’m missing

Vikki [24]

Step-by-step explanation:

$\overline{DA} \text{ bisects } \overline{EB}$ is given

$\overline{BC} \cong \overline{EC}$ definition of <u>bisect</u>

<u /> $\overline{EB} \perp \overline{ED}, \, \overline{EB} \perp \overline{BA}$ are both given

<u /> $\angle B, \, \angle E \text{ are right angles}$ definition of perpendicular

$\angle B \cong \angle E$ because all right angles are congruent

$\angle{ACB} \cong \angle{DCE}$ vertical angles are congruent

$\triangle{ACB} \cong \triangle{DCE}$ ASA (angle-side-angle)

$\overline{ED} \cong \overline{BA}$ CPCTC (corresponding parts of congruent triangles are congruent)

5 0

2 years ago