Answer:
x = 4.4
Step-by-step explanation:
I'm going to assume you want to solve for x so here we go.
You need to work backwards for this equation, and whatever you do to the LHS, you do to the RHS.
First, you need to remove the minus 3, which means that on both sides, you add 3. Adding three on the LHS makes the -3 disappear, and adding 3 on the RHS makes the 19 go to a 22.
Your equation is now 5x=22.
Since 5x means 5 × x, to get rid of it, you need to divide 5x by 5. Doing it to the LHS will make the five disappear, and doing it to the RHS will make it go to 22 ÷ 5 which equals 4.4
Therefore, x = 4.4
The square root of thirty lies between the numbers 5 and 6.
Answer: 3 hours and 50 min
Step-by-step explanation:look at each answer
Subtract it from 920 and then you have 530
In dividing two equation with variables and exponent, First you must align or rearrange the equation and group them base on their variables but don't forget the sign of each variables. Second, proceed in dividing its quantity and then subtract its exponent to the other variables having the same. So by calculating it, the answer would be X or X^1
Answer:
(12,-6)
Step-by-step explanation:
we have
----> inequality A
---> inequality B
we know that
If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)
<u><em>Verify each point</em></u>
Substitute the value of x and the value of y of each ordered pair in the inequality A and in the inequality B
case 1) (0,-1)
Inequality A

----> is true
Inequality B

----> is not true
therefore
The ordered pair is not a solution of the system
case 2) (0,3)
Inequality A

----> is true
Inequality B

----> is not true
therefore
The ordered pair is not a solution of the system
case 3) (-6,-6)
Inequality A

----> is true
Inequality B

----> is not true
therefore
The ordered pair is not a solution of the system
case 4) (12,-6)
Inequality A

----> is true
Inequality B

----> is true
therefore
The ordered pair is a solution of the system (makes true both inequalities)