61.)4+5(p-1)=34
4+5p-5=34
5p-1. =34
5p=34+1
5p=35
p=35/5
p=7
62)Let the smaller of the two supplementary angles be x°
x+(x+50°)=180
2x+50=180
2x=180-50
2x=130°
x=65°
(x+50)=65+50=115°
63) Since base angles of an isosceles triangle are equal
And ∆BAC is an isosceles triangle
Therefore, ∆BAC=∆BCD
64)Let selling price be y
Let cost price be x
If profit=10%
Selling price= Cost price+profit
Selling price=100%+10% of cost price
Selling price=110% of cost price
Rs. 5500=110/100 of cost price
Rs. 5500×100/110=cost price
Cost price=Rs. 5000
65)baseDL=4cm, perpendicular heights=12cm
area of parallelogram=4×12=48cm²
baseAD=8cm, perpendicular heightsBM=?
area of parallelogram=48cm²
area of parallelogram= baseAD× perpendicular heightsBM
48cm²=8cm×perpendicular heights BM
perpendicular heightsBM=48/8=6cm
area of bigger sheet 8cm =πr²
=3.14×8²
=3.14×64
=200.96cm²
area of smaller sheet 6cm=πr²
=3.14×6²
=3.14×36
=113.04cm²
Area remaining=200.96-113.04
=87.92cm²
SORRY BRO THIS IS ALL I COULD DO
HOPE IT HELPS AND UH.......
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