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3 years ago

CAN I GET A MC PICK TOTOROTOTOTOOTOTOTOTOTOTOTOTOTOTOOOOOOOOO

Mathematics

2 answers:

nordsb [41]3 years ago

8 0

Answer:

***T O O T***

ipn [44]3 years ago

4 0

Answer:THXXXXXXXSSSSS FOR THE POINTS

Step-by-step explanation:

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Answer:

how are we supposed to know that

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3 years ago

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Find the surface area of the right triangle prism(above) using the net (below)

kifflom [539]

Answer:

144

Step-by-step explanation:

2( 1/2 × 3 × 4 ) + ( 11 × 5) + ( 11 × 4 ) + ( 11 × 3)

= 12 + 55 + 44 + 33

= 144

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2 years ago

The first term in a sequence is 3<br> The term-to-term rule is + 8<br> What is the 5th term?

galben [10]

2nd term: 3+8
= 11
3rd term: 11+8
= 19
4th term: 19+8
= 27
5th term: 27+8
= 35

OR
((n-1)x8)+3

7 0

3 years ago

A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular

Oksi-84 [34.3K]

Answer:

The approximate are of the inscribed disk using the regular hexagon is $A=18\sqrt{3}\ units^2$

Step-by-step explanation:

we know that

we can divide the regular hexagon into 6 identical equilateral triangles

see the attached figure to better understand the problem

The approximate area of the circle is approximately the area of the six equilateral triangles

Remember that

In an equilateral triangle the interior measurement of each angle is 60 degrees

We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon

Let

M ----> the mid-point of AB

OM ----> the perpendicular bisector of AB

x ----> the measure of angle AOM

$m\angle AOM =30^o$

In the right triangle OAM

$tan(30^o)=\frac{(a/2)}{r}=\frac{a}{2r}\\\\tan(30^o)=\frac{\sqrt{3}}{3}$

$\frac{a}{2r}=\frac{\sqrt{3}}{3}$

we have

$r=3\ units$

substitute

$\frac{a}{2(3)}=\frac{\sqrt{3}}{3}\\\\a=2\sqrt{3}\ units$

Find the area of six equilateral triangles

$A=6[\frac{1}{2}(r)(a)]$

simplify

$A=3(r)(a)$

we have

$r=3\ units\\a=2\sqrt{3}\ units$

substitute

$A=3(3)(2\sqrt{3})\\A=18\sqrt{3}\ units^2$

Therefore

The approximate are of the inscribed disk using the regular hexagon is $A=18\sqrt{3}\ units^2$

6 0

3 years ago

PLSSSS HELP ME I WILL GIVE BRAINLY

tamaranim1 [39]

It’s y= 30x + 200 for the linear equation and the answer is 440

8 0

3 years ago