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2 years ago

CAN I GET A MC PICK TOTOROTOTOTOOTOTOTOTOTOTOTOTOTOTOOOOOOOOO

Mathematics

2 answers:

nordsb [41]2 years ago

8 0

Answer:

***T O O T***

ipn [44]2 years ago

4 0

Answer:THXXXXXXXSSSSS FOR THE POINTS

Step-by-step explanation:

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If the risk-free rate is 7 percent, the expected return on the market is 10 percent, and the expected return on Security J is 13

Lelu [443]

Answer:

0.02 or 2% = Beta

Step-by-step explanation:

Given that,

Risk-free rate = 7 percent

Expected return on the market = 10 percent

Expected return on Security J = 13 percent

Therefore, the beta of Security J is calculated as follows;

Expected return on Security J = Risk-free rate + Beta (Expected return on the market - Risk-free rate)

13 percent = 7 percent + Beta (10 percent - 7 percent)

0.13 - 0.07 = 0.03 Beta

0.06 = 0.03 Beta

0.06 ÷ 0.03 = Beta

0.02 or 2% = Beta

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2 years ago

A rectangle is bounded by the x-axis and the semicircle y = √(36 – x^2). Write the area A of the rectangle as a function of x, a

Dafna11 [192]

A(x)=2x·√36-x²
this is the answer.

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2 years ago

If a new data point at 12 is added to the graph, which will be true?

love history [14]

Answer:

the answer is C on edge

7 0

3 years ago

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What is the remainder of (4x2 + 7x-1)= (4 + x)?<br>A. -9x – 1<br>B.23x – 1<br>C.35<br>D.-37

bearhunter [10]

Answer: I don't know what you meant by remainder but i hope this helps :)

$x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}\\$

Step-by-step explanation:

$\left(4x^2+7x-1\right)=\left(4+x\right)\\\mathrm{Refine}\\4x^2+7x-1=4+x\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\4x^2+7x-1-x=4+x-x\\Simplify\\4x^2+6x-1=4\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\4x^2+6x-1-4=4-4\\\mathrm{Simplify}\\4x^2+6x-5=0\\\mathrm{For\:}\quad a=4,\:b=6,\:c=-5:\\\quad x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}$

$\frac{-6+\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\=\frac{-6+\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{8}\\\\Let\: simplify\: ; -6+2\sqrt{29}\\=-2\times \:3+2\sqrt{29}\\=2\left(-3+\sqrt{29}\right)\\=\frac{2\left(-3+\sqrt{29}\right)}{8}\\=\frac{-3+\sqrt{29}}{4}\\$

$\frac{-6-\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\\\=\frac{-6-\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\\\=\frac{-6-\sqrt{116}}{2\times \:4}\\\\=\frac{-6-2\sqrt{29}}{8}\\\\=-\frac{2\left(3+\sqrt{29}\right)}{8}\\\\=-\frac{3+\sqrt{29}}{4}\\\\\\x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}$

6 0

2 years ago

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What is the soulution of the equation 3(2x+5)=3x+4

lakkis [162]

x=- $\frac{11}{3}$

x=-3.666666666666666666666666666666666666666666666

8 0

2 years ago

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