A three digit number would be 294. You could do 200+90+4
We have that
point C and point D have y = 0-----------> (the bottom of the trapezoid).
point A and point B have y = 4e ---------- > (the top of the trapezoid)
the y component of midpoint would be halfway between these lines
y = (4e+ 0)/2 = 2e.
<span>the x component of the midpoint of the midsegment would be halfway between the midpoint of AB and the midpoint of CD.
x component of midpoint of AB is (4d + 4f)/2.
x component of midpoint of CD is (4g + 0)/2 = 4g/2.
x component of a point between the two we just found is
[(4d + 4f)/2 + 4g/2]/2 = [(4d + 4f + 4g)/2]/2 = (4d + 4f + 4g)/4 = d + f + g.
</span>therefore
the midpoint of the midsegment is (d + f + g, 2e)
X
+
6
−
5
=
8
−
2
+
6
−
5
=
8
−
2
Solve
1
Subtract the numbers
x
+
6
−
5
=
8
−
2
+
6
−
5
=
8
−
2
x
+
1
=
8
−
2
+
1
=
8
−
2
2
Subtract the numbers
x
+
1
=
8
−
2
+
1
=
8
−
2
x
+
1
=
6
+
1
=
6
3
Subtract
1
1
from both sides
x
+
1
=
6
+
1
=
6
x
+
1
−
1
=
6
−
1
+
1
−
1
=
6
−
1
4
Simplify
Subtract the numbers
Subtract the numbers
x
=
5
=
5
Answer: A 1 to 4
Step-by-step explanation:
