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3 years ago

Help I don’t know the steps

Mathematics

1 answer:

Korvikt [17]3 years ago

7 0

Answer:

down below

Step-by-step explanation:

straight lines are 180 degrees and you have 2 angles on a line. one of which is 72 and the other is unknown. It is solved for below.

$180=72+x\\180-72=72+x-72\\108=x$

your missing degree is 108.

i may not be right, if i'm not i am very sorry.

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A school needs 138 5 meters of fencing for a new playground Fencing is

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Answer:

12 Sections

Step-by-step explanation:

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3 years ago

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A dog collar was originally priced at $5 but went on sale for 20% off. If Vince bought the dog collar and paid 9% sales tax, how

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Answer:$4.36

Step-by-step explanation:

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3 years ago

PLEAAASE HELPP that would be very much appreciated

DIA [1.3K]

Answer:

h(x) = (x + 4)^2 - 2

Step-by-step explanation:

Start with the red graph: f(x) = x^2

First we move the entire graph 4 units to the left. The resultant function is g(x) = (x + 4)^2.

Next, we move this latest graph 2 units down. The resultant function (and answer to this question) is h(x) = (x + 4)^2 - 2

8 0

3 years ago

Identify the standard form of the equation by completing the square.

OLEGan [10]

Answer:

$\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Step-by-step explanation:

<u>Given equation</u>:

$4x^2-9y^2-8x+36y-68=0$

This is an equation for a horizontal hyperbola.

<u>To complete the square for a hyperbola</u>

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

$\implies 4x^2-8x-9y^2+36y=68$

Factor out the coefficient of the x² term and the y² term.

$\implies 4(x^2-2x)-9(y^2-4y)=68$

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

$\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2$

$\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36$

Factor the two perfect trinomials on the left side:

$\implies 4(x-1)^2-9(y-2)^2=36$

Divide both sides by the number of the right side so the right side equals 1:

$\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}$

Simplify:

$\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Therefore, this is the standard equation for a horizontal hyperbola with:

center = (1, 2)
vertices = (-2, 2) and (4, 2)
co-vertices = (1, 0) and (1, 4)
$\textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}$
$\textsf{Foci}: \quad (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)$

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2 years ago