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aalyn [17]
3 years ago
6

Help I don’t know the steps

Mathematics
1 answer:
Korvikt [17]3 years ago
7 0

Answer:

down below

Step-by-step explanation:

straight lines are 180 degrees and you have 2 angles on a line. one of which is 72 and the other is unknown. It is solved for below.

180=72+x\\180-72=72+x-72\\108=x

your missing degree is 108.

i may not be right, if i'm not i am very sorry.

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It costs $6.45 to buy 5 songs on I-tunes. How much does it cost to buy 20 songs?
babunello [35]

Answer:$25.80

Step-by-step explanation:

6.45/5 = 1.29

1.29 x 20 =25.80

5 0
2 years ago
In the right triangle, a = 20, b = 21. Find c<br><br> A) 841<br> B) 22<br> C) 29
Mariulka [41]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
Can someone help me with this?​
Anna35 [415]

Answer:

Let 'a' be the first term, 'r' be the common ratio and 'n' be the number of terms

Series = 2+6+18.......= 2+2•3¹+ 2•3².......= 728

Now,

Sum =  \frac{a( {r}^{n} - 1) }{(r - 1)}   \\

So,

\frac{a( {r}^{n} - 1)}{(r - 1)}  = 728 \\  \frac{2( {3}^{n} - 1) }{(3 - 1)}  = 728 \\  \frac{2( {3}^{n} - 1) }{2}  = 728 \\  {3}^{n}  - 1 = 728 \\ {3}^{n}=728+1\\ {3}^{n}  = 729 \\  {3}^{n}  =  {3}^{6}  \\ \boxed{ n = 6}

Therefore, number of terms is 6

  • 6 is the right answer.
3 0
3 years ago
What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?
Harman [31]

Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{ \: 14.25 \: \% \: }}}}}

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

\boxed{ \sf{Amount =  \: Principal + Interest}}

plug the values

⇒\sf{14550 = 6000 + Interest}

Swap the sides of the equation

⇒\sf{6000 + Interest = 14550}

Move 6000 to right hand side and change its sign

⇒\sf{Interest = 14550 - 6000}

Subtract 6000 from 14550

⇒\sf{Interest = \: 8550 \: }

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

{ \boxed{ \sf{Rate =  \frac{Interest \times 100}{Principal \times Time}}}}

plug the values

⇒\sf{ Rate = \frac{8550  \times 100}{6000 \times 10} }

Calculate

⇒\sf{Rate =  \frac{855000}{60000} }

⇒\sf{Rate = 14.25 \: \% \: }

Hope I helped!

Best regards!!

8 0
3 years ago
Dan had a large piece of wood that was 10 feet
Doss [256]

Answer:

40 pieces of wood

Step-by-step explanation:

Find how many pieces he cut by dividing 10 by 1/4

10 / (1/4)

= 40

So, Dan cut 40 pieces of wood

7 0
3 years ago
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