Part a.
u = 0, the initial velocity
v = 60 mi/h, the final velocity
a = 2.35 m/s², the acceleration.
Note that
1 m = 1609.34 m.
Therefore
v = (60 mi/h)*(1609.34 m/mi)*(1/3600 h/s) = 26.822 m/s
Use the formula
v = u + at
(26.822 m/s) = (2.35 m/s²)*(t s)
t = 26.822/2.35 = 11.4 s
Answer: 11.4 s
Part b.
We already determined that v = 60 mi/h = 26.822 m/s.
t = 0.6 s
Therefore
(26.822 m/s) = (a m/s²)*(0.6 s)
a = 26.822/0.6 = 44.7 m/s²
Answer: 44.7 m/s²
Answer:
D. Checking to see if the brake fluid is contaminated
Explanation:
Answer:
Gas 2, Gas 3, Gas 4, Gas 5 is the order of decreasing strength of inter-molecular forces.
Explanation:
The strength increases as there is a decrease in the vanderwaals constant and vice versa.
The amplitude of a wave can be obtained by measuring the distance from the resting position of the wave to its crest. The resting position is half of the distance from the crest to the trough. Given that the distance between the crest and the trough is 3 meters, the amplitude should be half of that, which is 1.5 meters.
Answer:
Explanation:
Formula and givens
- λ = c / f
- λ is the wavelength
- c = the speed of light
- f = the frequency
- c = 3*10^8
- f = 7.89 * 10^14
λ = ?
Solution
λ = 3*10^8 / 7.89*10^14
λ = 3*10^8/7.89*10^14
λ = 2.36 * 10^7
λ = 236 nanometers. What you use as your solution depends on what what you have been taught.
