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schepotkina [342]

3 years ago

10

When both momentum and kinetic energy are conserved,

2 answers:

tiny-mole [99]3 years ago

8 0

Answer:

Elastic collision

Explanation:

An elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision. Both momentum and kinetic energy are conserved quantities in elastic collisions. Supposed two similar trolleys are traveling toward each other with equal speed.

brilliants [131]3 years ago

4 0

Answer:

ijmuygbers

Explanation:

mijuhg6rty

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The image above shows a block pulled across a table. The spring scale which measures in Newtons, reads the force resisting the m

insens350 [35]

The correct answer is D. friction force

6 0

3 years ago

Read 2 more answers

Which formulas have been correctly rearranged to solve for radius? Check all that apply. r = GM central/v^2 r =fcm/v^2 r =ac/v^2

jek_recluse [69]

The orbital radius is: $r=\frac{GM}{v^2}$

Explanation:

The problem is asking to find the radius of the orbit of a satellite around a planet, given the orbital speed of the satellite.

For a satellite in orbit around a planet, the gravitational force provides the required centripetal force to keep it in circular motion, therefore we can write:

$\frac{GMm}{r^2}=m\frac{v^2}{r}$

where

G is the gravitational constant

M is the mass of the planet

m is the mass of the satellite

r is the radius of the orbit

v is the speed of the satellite

Re-arranging the equation, we find:

$\frac{GM}{r}=v^2\\r=\frac{GM}{v^2}$

Learn more about circular motion:

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7 0

3 years ago

Read 2 more answers

1. How much force would you have to apply to a 15kg object in order to accelerate it!<br> a 2 m/s?

mihalych1998 [28]

30N

Explanation:

Given parameters:

Mass of object = 15kg

Acceleration = 2m/s

Unknown:

Force = ?

Solution:

Force is given as the product of mass and acceleration:

F = m x a

m is the mass

a is the acceleration

Inputting the parameters:

F = 15 x 2 = 30N

The unit of force is newtons, N .

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3 0

3 years ago

If you walk 3 meters north and then 4 meters west, what is the magnitude of your displacement?

ankoles [38]

S^2=3^2+4^2
S^2=9+16
S^2=25
S=√25
S=5m

7 0

3 years ago

Scientists have investigated how quickly hoverflies start beating their wings when dropped both in complete darkness and in a li

Vesna [10]

Answers:

A) 0.204 m

B) 0.285 s

Explanation:

<h2>Answer A:</h2>

This described situation is free fall, this means the initial velocity of the fly is zero, and the equation that will be used is:

$y=y_{o}+V_{o}t-\frac{1}{2}gt^{2}$ (1)

Where:

$y$ is the final height of the fly

$y_{o}=40 cm=0.4 m$ is the initial height of the fly

$V_{o}=0$ is the initial velocity of the fly

$t=200(10)^{-3} s$ is the time

$g=9.8 m/s^{2}$ is the acceleration due to gravity

$y=0.4 m+0-\frac{1}{2}(9.8 m/s^{2})(200(10)^{-3} s)^{2}$ (2)

$y=0.204 m$ (3) This is the distance at which the fly would begin to beat its wings

<h2>Answer B:</h2>

In this part we will also use equation (1), but we will find the time:

$y=y_{o}+V_{o}t-\frac{1}{2}gt^{2}$ (1)

Where:

$y=0$ is the final height of the fly

$y_{o}=40 cm=0.4 m$ is the initial height of the fly

$V_{o}=0$ is the initial velocity of the fly

$t$ is the time we need to find

$g=9.8 m/s^{2}$ is the acceleration due to gravity

$0=0.4 m+0-\frac{1}{2}(9.8 m/s^{2})t^{2}$ (4)

Isolating $t$ :

$t^{2}=\frac{(-2)(-0.4 m)}{9.8 m/s^{2}}$ (5)

$t=0.285 s$ (6) This is the time it would take for a fly to hit the bottom of the box

6 0

4 years ago