All categories

3 years ago

Which three statements describe ways that earth's astmosphere protects living things

Biology

1 answer:

Otrada [13]3 years ago

4 0

Answer:

The atmosphere blocks out harmful rays from the sun. The ozone layer, which lies in the stratosphere 11 to 50 kilometers from the Earth's surface, blocks out many harmful forms of radiation. Without the ozone layer, ultraviolet rays would destroy most life on Earth. Gases in the atmosphere also hold in heat.

You might be interested in

Which of the following accurately describes fermentation? A. All types of fermentation produce carbon dioxide. B. Fermentation c

Tom [10]

The correct answer is C. Fermentation makes NAD+ needed to keep glycolysis going. The other options are inaccruate since:
for A: there are types of fermentation that does not produce carbon dioxide like Lactic acid fermentation
for B: many types of fermentation only occurs in the absence of oxygen (anaerobic process)
for B: respiration produces around 36 ATP while fermentation only generates around 2 ATP

7 0

4 years ago

All of the following are important properties of prokaryotes except

frozen [14]

All of the following are important properties of prokaryotes except prokaryotes convert nitrogen-containing molecules into forms that can't be used by other organisms.

4 0

3 years ago

Read 2 more answers

You cross two true-breeding parents (one with yellow seeds and one with green seeds), grow and self-pollinate the F1 generation,

Andru [333]

Answer:

1500

Explanation:

Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.

The total population size of F2 generation = 2000

The proportion of yellow seeded plants in F2 generation = 3/4 (since the F2 phenotype ratio is given 3 yellow: 1 green)

Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500

3 0

3 years ago

P450 encodes an enzyme that detoxifies insecticides. Abc8 encodes a transporter protein thatpumps insecticides out of cells. Cps

babymother [125]

Answer:yes

Explanation:

3 0

3 years ago

If you have a pet cockroach with a brown body, how could you find out if it is

aleksklad [387]

Answer:

by testcrossing with a homozygous recessive partner

Explanation:

If a pet cockroach exists whose zygosity is unknown, this can be determined by a test cross. A test cross involves crossing an organisms whose zygosity is unknown with a partner that is homozygous recessive for the same trait.

Let us assume that brown body is represented by the allele B, the dominant allele. The homozygous recessive version would be bb.

The genotype of a brown cockroach whose zygosity is not known can be denoted as B_, where '_' can be a 'B' or a 'b'.

When B_ is crossed with bb:

B_ x bb

Progeny

2 Bb

2 _b

The phenotype of Bb would be brown (since B is dominant over b) while the phenotype of _b would depend on the zygosity level of the cockroach.

If the unknown genotype is BB, then _b becomes Bb and the phenotype will be a brown body. This means that all the progeny will appear brown. (see the first attached image for the Punnet's square)

In other word, if the unknown genotype is bb, then _b becomes bb and the phenotype will be a alternate color (non-brown) body. This means that 50% of the progeny will appear brown while the remaining 50% will be in the alternate color. (attached

3 0

4 years ago