Answer:
i would say the 3rd one
Step-by-step explanation:
Given three points, it is possible to draw a circle that passes through all three. The perpendicular bisectors of a chords always passes through the center of the circle. By this method we find the center and can then draw the circle. This is virtually the same as constructing the circumcircle a triangle.
<span> sorry it's such a long answer 111.278928823</span>
The sequence is geometric, so

for some constant r. From this rule, it follows that

and we can determine the first term to be

Now, by substitution we have

and so on down to (D)

(notice how the exponent on r and the subscript on a add up to n)
Answer:
kg.
Step-by-step explanation:
Let S be amount of strawberries picked in the afternoon.
We have been given that Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg less strawberries in the morning than in the afternoon and the strawberries picked in morning are
kg.
To find the amount of strawberries picked by Sheldon in the afternoon we will add
and
:
Upon converting our given mixed fractions into improper fraction we will get,

Now let us have a common denominator.


Therefore, Sheldon picked
kg of strawberries in the afternoon.
It's a probability problem to find the odds of picking a green or red
shirt out of the 10 shirts on Thursday, Friday and Saturday since you
have randomly already know you have picked a blue shirt on the other
days. Not sure if you have this as a multiple question problem as you didn't list any possible answers (A. 7/20, B. 5/47, C. 2/5, D. 4/125) to the question. A, B, C, D being like 7 chances out of 20, 5 chances out 47, 2 chances out of chances 5 or 4 chances out of 125 (example answers only).
Probability = Number favorable outcomes / total number of outcomes