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3 years ago

Somebody please explain this to me and help me!!!

Mathematics

2 answers:

marissa [1.9K]3 years ago

6 0

Answer:

This question is so complex

Step-by-step explanation:

kfdsjbdsnmvn sdbvjhsbadjvm dashbnvdjnzcxshjd

pogonyaev3 years ago

3 0

Answer:

1) 3,3

2) 4,5

3) 6,1

4) 1/36

There are 36 possible outcomes when you roll a dice. Rolling two 3s is only one of the possible outcomes. Therefore, the fraction 1/36 can represent this probability.

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I need help with this question please help me .

kenny6666 [7]

We need to find the mean of a set of five values.

In order to do so, we need to add all the values, and then divide the result by the total number of values.

So, adding those values, we obtain:

$-67-65-71-59-73=-335$

Notice that since they are all negative values, the result is the sum of their absolute values with the minus sign.

Now, since the total number of values in the given set is 5, we need to divide the previous result by 5. We obtain:

$\frac{-335}{5}=-67$

4 0

1 year ago

A polnt represents:

Allushta [10]

A point represents a location. A coordinate on a plane .

The intersection of two planes is a line.

5 0

3 years ago

Write an algebraic expression. Multiply the sum of 4 and a number (n) by 3.

SVETLANKA909090 [29]

The answer could look sumn like this 4+n(3)

4 0

3 years ago

A metal can in the shape of a right circular cylinder needs to hold a volume of V cm3 . Throughout this problem V > 0 is a pa

belka [17]

Answer:

C(min) = 0.5*V + √V/1.256 $

Step-by-step explanation:

The volume of a circular cylinder is: V(c) = π*r²*h where r is the radius of the circumference of the base and h is the height

The cost of the can is = the cost of (base and top) + lateral cost

Base surface = top surface = π*r²

Then cost of ( base + top ) is = (2* π*r² )*0,1

Lateral surface is = 2*π*r*h

Then cost of lateral surface is: (2*π*r*h)*0,5

Total cost C(t) = (2* π*r² )*0,1 + (2*π*r*h)*0,5

V = π*r²*h

Total cost as a function of (V >0 a parameter) and r then

h = V / π*r²

C(V,r) = (2* π*r² )*0,1 + π*r*(V / π*r²)

C(V,r) = 0.2*π*r² + V*/r

Taking derivatives on both sides of the equation we get:

C´(V,r) = 2*0.2*π*r - V/r²

C´(V,r) = 0 0.4*π*r - V/r = 0

Solving for r

0.4*π*r² - V = 0 ⇒ 1.256*r² = V r = √ V/ 1.256 cm

and h = V /π * (√ V/ 1.256)²

h = 1/ 1.256*π

h = 0.254 cm

C(V,r) = 0.2*π*r² + V*/r

C(min) = 0.2*π* (√ V/ 1.256)² + V/ √ V/ 1.256

C(min) = 0.2*π*V/1.256 + V/ √ V/ 1.256

C(min) = 0.5*V + √V/1.256 $

6 0

3 years ago

Consider the radical equation (3√6-x)+4=-8. Explain why the calculation in Problem 1 does not produce a solution to the equation

murzikaleks [220]

Answer:

See explanation below

Step-by-step explanation:

First we will solve the radical equation (which I guess was problem 1),

Let's start by simplifying it:

$3\sqrt{6-x}+4=-8\\ 3\sqrt{6-x}=-8-4\\ 3\sqrt{6-x}=-12\\\sqrt{6-x}=-4$

Now we will solve the equation by squaring both sides of the equation:

$\sqrt{6-x} =-4\\6-x=-4^{2} \\6-x=16\\-x=16-6\\-x=10\\x=-10$

So the calculation for x was that x = -10

However, this does not produce a solution to the equation: When we plug this value into the radical equation we get:

$3\sqrt{6-x} +4= -8\\3\sqrt{6-(-10)} +4=-8\\3\sqrt{16}+4 = -8\\ 3(4)+4 = -8\\12 + 4 = -8$

This happens because when we first squared both sides of the equation in the first part of the problem we missed one value for x (remember that all roots have 2 answers, a positive one and a negative one) while squares are always positive.

When we squared the root, we missed one value for x and that is why the calculation does not produce a solution to the equation.

6 0

3 years ago