All categories

3 years ago

Write the fraction as a percent. 1/400

Mathematics

2 answers:

svet-max [94.6K]3 years ago

8 0

Answer:

0.25%

Step-by-step explanation:

alexgriva [62]3 years ago

7 0

Answer:

0.25%

Step-by-step explanation:

1/4 = 0.25

1/40 = 0.025

1/400 = 0.0025 = 0.25%

Answer: 0.25%

You might be interested in

Haruka hiked several kilometers in the morning. She hiked only 6 kilometers in the afternoon, which was 25%, percent less than s

Semenov [28]

Answer:

14 km

Step-by-step explanation:

6 km in the afternoon

x km in the morning

6= x- 25%

6= 0.75x

x= 6/0.75

x= 8 km

total 6+8= 14 km

4 0

3 years ago

Please help!!!! No explanation needed <br> Help is appreciated

Elodia [21]

Answer:

-Brain Indigo

8 0

3 years ago

Steps to solve 3 raised tobthe power of 6

SVETLANKA909090 [29]

Times 3 6 times but not 3 times 6

7 0

3 years ago

Read 2 more answers

Out of 450 applicants for a job, 206 are male and 62 are male and have a graduate degree.

xxMikexx [17]

Answer:

0.3009 is the probability that the applicant has graduate degree given he is a male.

Step-by-step explanation:

We are given he following in the question:

M: Applicant is male.

G: Applicant have a graduate degree

Total number of applicants = 450

Number of male applicants = 206

$n(M) = 206$

Number of applicants that are male and have a graduate degree = 62

$n(M\cap G) = 62$

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

$P(M) = \dfrac{206}{450} = 0.4578$

$P(M\cap G) = \dfrac{n(M\cap G)}{n} = \dfrac{62}{450} = 0.1378$

We have to find the probability that the applicant has graduate degree given he is a male.

$P(G|M) = \dfrac{P(G\cap M)}{P(M)} = \dfrac{\frac{62}{450}}{\frac{206}{450}} = \dfrac{62}{206} = 0.3009$

Thus, 0.3009 is the probability that the applicant has graduate degree given he is a male.

5 0

3 years ago

Find the sum of first 15 terms of an AP whose 4th and 9th t terms are -15 and -30 respectively.

Serga [27]

Answer:

Sum of the first 15 terms = -405

Step-by-step explanation:

a + 3d = -15 (1)

a + 8d = -30 (2)

Where,

a = first term

d = common difference

n = number of terms

Subtract (1) from (1)

8d - 3d = -30 - (-15)

5d = -30 + 15

5d = -15

d = -15/5

= -3

d = -3

Substitute d = -3 into (1)

a + 3d = -15

a + 3(-3) = -15

a - 9 = -15

a = -15 + 9

a = -6

Sum of the first 15 terms

S = n/2[2a + (n − 1) × d]

= 15/2 {2×-6 + (15-1)-3}

= 7.5{-12 + (14)-3}

= 7.5{ -12 - 42}

= 7.5{-54}

= -405

Sum of the first 15 terms = -405

7 0

2 years ago